The magnetic relay in the figure has a coil of 500 turns currying a urrent I=4,19 A. The mean core path length is 1. = 360 mm and the Core Mean path ir gap is = 1,5 mm. The relative permeability of the core is u%31250 and its cross-section is A. =100 mm2. Neglect flux fringing n the air gaps. ) Draw the equivalent magnetic circuit of the relay and calculate its parameters, (MMF and reluctances) ) Calculate the flux density in the air gap (use the circuit in (a)) =) Calculate the total force acting on the moving part Simplified magnetic relay.

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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The magnetic relay in the figure has a coil of 500 turns currying a
current I = 4,19 A. The mean core path length is l. = 360 mm and the
air gap is = 1,5 mm. The relative permeability of the core is
Core
Mean path
H. =1250 and its cross-section is A. =100 mm?. Neglect flux fringing
in the air gaps.
a) Draw the equivalent magnetic circuit of the relay and calculate its
parameters, (MMF and reluctances)'
b) Calculate the flux density in the air gap (use the circuit in (a))
c) Calculate the total force acting on the moving part
Simplified magnetic
relay.
Transcribed Image Text:The magnetic relay in the figure has a coil of 500 turns currying a current I = 4,19 A. The mean core path length is l. = 360 mm and the air gap is = 1,5 mm. The relative permeability of the core is Core Mean path H. =1250 and its cross-section is A. =100 mm?. Neglect flux fringing in the air gaps. a) Draw the equivalent magnetic circuit of the relay and calculate its parameters, (MMF and reluctances)' b) Calculate the flux density in the air gap (use the circuit in (a)) c) Calculate the total force acting on the moving part Simplified magnetic relay.
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