College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- An electrically conductive rod is moving through a uniform magnetic flux at a constant velocity at right angles, as shown by its cross-section in the diagram. The velocity is in the x-direction, the rod is of length 150 mm along z, and the magnetic flux density is 0.2 T in the positive y-direction. Speed If the potential difference (voltage) across the ends of the rod is 5.8 Volts, what is the magnitude of the velocity? m/s Not perpendicular If the rod is passing through the flux with its axis not at right angles what can you be sure of? The speed to generate 5.8 V would have to be smaller. • The speed to generate 5.8 V would have to be bigger. The speed to generate 5.8 V would be the same.arrow_forwardA circular piece of wire with radius 0.89 m has a 84.9 T magnetic field passing through. What is the maximum magnetic flux that can pass through this ring?arrow_forwardA 1450 turn coil of wire, 6.16 cm in diameter, is in a magnetic field that drops from 0.723 T to 0 T in 41.9 ms. The axis of the coil is parallel to the field. What is the emf (in V) of the coil?arrow_forward
- You wish to produce a 10 V potential difference along the length of a 0.2 m long metal rod by moving it through a magnetic field. If the field has a strength of 2 T, what minimum speed would be needed? 2 m/s 10 m/s 20 m/sarrow_forwardConsider a straight conductor of length 4.9 cm. The conductor moves at right angles to a magnetic field of uniform strength ?=10−3B=10−3 T generating e.m.f. of 2.5×10−52.5×10−5 V. Calculate the velocity of the straight conductor. Give your answer in SI units.arrow_forwardA circular coil enclosing an area of 140 cm? is made of 210 turns of copper wire (shown in the figure below). The wire making up the coil has no resistance; the ends of the wire are connected across a 3.00-N resistor to form a closed circuit. Initially, a 1.20-T uniform magnetic field points perpendicularly upward through the plane of the coil. The direction of the field then reverses so that the final magnetic field has a magnitude of 1.20 T and points downward through the coil. If the time interval required for the field to reverse directions is 0.200 s, what is the average current in the coil during that time? Rarrow_forward
- A solenoid has 15 turns per centimeter. What current will produce a magnetic field of 1.6×10−21.6×10−2 T within the solenoid? The required current is ________A.arrow_forwardIn (Eigure 1), the rod moves with a speed of 1.1 m/s on rails 33.0 cm apart. The rod has a resistance of 2.3 2. The magnetic field is 0.39 T, and the resistance of the U -shaped conductor is 24.0 2 at a given instant. Figure B (outward) vdt 1 of 1 Calculate the current in the U-shaped conductor. Express your answer to two significant figures and include the appropriate unit 1 = 0.43 HÅ Submit Previous Answers Request Answer Part C A X Incorrect; Try Again; 3 attempts remaining HA Calculate the external force needed to keep the rod's velocity constant at that instant Express your answer to two significant figures and include the appropriate un Pearson ? 7. T...arrow_forwardA stationary square coil of area 0.1 m2 is brought over time of 2 s into the magnetic field 8.5 T with its plane perpendicular to the magnetic field. The coil has 1523 turns. Calculate the magnetic flux linkage through the coil. Give your answer in SI units.arrow_forward
- An 18 cm diameter loop of wire consists of 28 turns of circular copper wire 2.5 mm indiameter. A uniform magnetic field, perpendicular to the plane of the loop, changes ata rate of 8.5 x 10-3 T/s. What is the current in the loop? The resistivity of copper is 1.68 x 10-8 W m. (Hint: solve for V and R, then solve for I)arrow_forwardShown in the figure below is a rectangle of wire immersed in a magnetic field. The rectangle has length L = 2 meters, width w = 2 meters, and a resistance of R = 7.97 Ω. The magnetic field varies with time according to the equation:B(t) = 5t2 + 2t5As a result of the varying field, a voltage and current will be established in the loop.Answer all of the following: What is the FORMULA for the rate of change of magnetic field with time, dB dt = What is the FORMULA for the rate of change of magnetic flux with time, dΦB dt = What is the voltage in the circuit at t=1.1 seconds? Volts What is the current in the circuit at this same time? Amps NOTE: Make all formulas POSITIVE (field and flux). Make all values POSITIVE (voltage and current). Format your equations as atn + btm where a,b,n,m are numerical values. Example: 12t2 + 72t3arrow_forwardA current loop of 2-m radius creates 5 T magnetic field at the center of the loop. A student makes a solenoid out of the same loop wire. He measures the length of the solenoid that is 37 cm and counts the number of turns (that is 76). Calculate the magnetic field at the center of the solenoid.arrow_forward
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