The lowest triplet state in naphtnalene (C10H8) is about below thne lowest excited by N2/N1 = (92/91)exp(-AE/kgT), where g1 and g2 are the degeneracies for levels 1 and 2.] N2 = 1.43e-90

Please only answer part ii

(Slightly modified McQuarrie 5-41) Many quantum vibrational states are available to molecules. This raises the question: In what vibrational states are molecules actually found? Using sta- tistical mechanics, one can show (see McQuarrie 5-40 if you are interested) that the fraction of molecules in the n-th state is given by: fn = (1-e-hv/kBT) e -nhv/kBT where kB is the Boltzmann constant, kg = 1.380658 × 10-23 J/K. Compute the occupancy of the n=0, 1 and 2 states at 300 K and 1500 K for a "typical" harmonic frequency, we = 2650 cm-1. For practical purposes, what vibrational state is a typical molecule found in?

Below is the resolved absorption spectrum of HBr for the vibrational transition v = 0 → V = 1; determine: (a) the effective spring constant for the molecular bond 35 and (b) the bond length. (c) Repeat for both the HCl 37 and H Cl spectra. (d) Based upon these results, explain your prediction regarding which molecule has the "strongest" bond and then explain whether your prediction is confirmed by looking up the corresponding bond dissociation energies. ✓ 2 0.300 0.310 0.320 0.330 0.340 Energy (eV)