The life expectancy of a male during the course ofthe past 100 years is approximately 27,715 days.Use the table to the right to conduct a test usinga=0.05 to determine whether the evidencesuggests that chief justices live longer than thegeneral population of males. Suggest a reasonwhy the conclusion drawn may be flawed.State the appropriate null and alternative hypotheses.O A. Ho: p=27,715 versus H₁: μ<27,715OC. Ho H=27,715 versus H₁: μ>27,715O E. Ho: p=30,747 versus H,: μ#30,747ChiefLifeChiefJustice Span (Days) JusticeAIJKLMN0PBCDEFGH31,07329,372Ioanngildin30,22728,91832,45232,62826,57732,592LifeSpan (Days)32,93427,432HERITATION30,629OB. Ho: H=27,715 versus H₁: p #27,715OD. Ho H=30,747 versus H₁: <30,747OF. Ho H=30,747 versus H₁: >30,747196730,93032.40728,31932,74132,716tedny

Answered: The life expectancy of a male during…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim about the population mean, µ, at the given level of significance using the given sample statistics. Claim: p = 30, a = 0.06; o = 3.25. Sample statistics: x= 28.9, n = 73 Identify the null and alternative hypotheses. Choose the correct answer below. A. Ho: H=30 H3: µ#30 O B. H, p 30 H3: µ= 30 OD Ho pt30 Ha p= 30 0F Ho p= 30 ΤΟΕ H6: μ= 30 H3:> 30 H, µ< 30 Calculate the standardized test statistic. The standardized test statistic is (Round to two decimal places as needed.)
A data set includes data from 400 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.6 miles. Use a 0.05 significance level. Use the display to identify the null and alternative hypotheses, test statistic, and P-value. State the final conclusion that addresses the original claim. Hypothesis test results: μ: Mean of variable Ho: μ=2.6 HA H>2.6 Variable Sample Mean Length 2.75311 Std. Err. DF T-Stat 0.274284 399 0.558217 P-value 0.2885 OA. Fail to reject Ho. There is sufficient evidence to support the claim that the mean tornado length is greater than 2.6 miles OB. Reject Ho. There is sufficient evidence to support the claim that the mean tornado length is greater than 2.6 miles OC. Reject Ho. There is not sufficient evidence to support the claim that the mean tornado length is greater than 2.6 miles. OD. Fail to reject Ho. There is not sufficient evidence to support…
The accompanying data are measured body temperatures of adults at 12 AM on a certain day. Use the Wilcoxon signed-ranks test to test the claim that the median is equal to 98.6°F. Use a 0.05 significance level. Click the icon to view the body temperature data. Determine the null and alternative hypotheses. Ho: The median body temperature is H₁: The median body temperature is (Type integers or decimals. Do not round.) Determine the P-value. The P-value is (Round to three decimal places as needed.) Determine the proper conclusion. Ho. There is ▼ ✔ evidence at the 0.05 significance level to warrant rejection of the claim that the median body temperature is C 98.6°F. Body Temperature Data 98.1 97.7 98.7 98.1 98.9 97.7 98.5 98.7 98.1 98.1 98.1 97.9 97.3 98.3 98.0 98.1 98.4 99.1 97.9 96.9 97.2 98.2 97.9 98.9 97.5 98.1 97.3 98.1 98.5 98.5 96.9 98.5 98.1 99.3 97.7 98.3 98.9 97.8 98.1 98.0 98.6 97.3 98.4 98.6 98 7 99.0 97.3 97.5 98.0 98.1 98.6 98.7 98.7 98.7 99.2 97.7 97.7 98.5 97.6 99.4 97.6…
A data set includes data from 400 random tornadoes. The display from the technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.1 miles. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Hypothesis test results: μ : Mean of variable H0 : μ=2.1 HA : μ>2.1 Variable Sample Mean Std. Err. DF T-Stat P-value Length 2.63613 0.288165 399 1.860497 0.0318 p Part 1 Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses
Next question A golf association requires that golf balls have a diameter that is 1.68 inches. To deter hform to the standard, a random sample of golf balls was selected. Their diameters are shown in the accompanying data table. Do the golf balls conform to the standards? Use the x = 0.01 level of significance. Click the icon to view the data table. First determine the appropriate hypotheses. Ho: H₁: (Type integers or decimals. Do not round.) Find the test statistic. (Round to two decimal places as needed.) Find the P-value. (Round to three decimal places as needed.) What can be concluded from the hypothesis test? O A. Reject Ho. There is sufficient evidence to conclude that the golf balls do not conform to the association's standards at the α = 0.01 level of significance. B. Do not reject Ho. There is not sufficient evidence to conclude that the golf balls do not conform to the association's standards at the x = 0.01 level of significance. C. Do not reject Ho. There is sufficient…
Use the pulse rates in beats per minute (bpm) of a random sample of adult females listed in the data set available below to test the claim that the mean is less than 79 bpm. Use a 0.05 significance level. LOADING... Click the icon to view the pulse rate data. Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. H0: μ=79 bpm H1: μ≠79 bpm B. H0: μ>79 bpm H1: μ<79 bpm C. H0: μ=79 bpm H1: μ<79 bpm D. H0: μ=79 bpm H1: μ>79 bpm Determine the test statistic. nothing (Round to two decimal places as needed.) Determine the P-value. nothing (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. ▼ Reject Fail to reject H0. There is ▼ not sufficient sufficient evidence to conclude that the mean of the population of pulse rates for adult females is ▼ greater than not less than…
Select the most appropriate response. It is claimed that the mean age of bus drivers in Chicago is 59.3 years. If a hypothesis test is performed, how should you interpret a decision that fails to reject the null hypothesis? Question 2 options: There is not sufficient evidence to reject the claim µ = 59.3. There is sufficient evidence to reject the claim p = 59.3. There is not sufficient evidence to support the claim p = 59.3. There is sufficient evidence to support the claim u = 59.3.
Can I have all 3 questions done, Thank you.
Find the test statistic: Determine the P-value: State the final conclusion that addresses the original claim:
Use a significance level of a=0.05 to test the claim that μ=19. The sample data consists of 15 scores for which x=20.4 and s=4.8. State the null and alternative hypotheses, compute the value of the test statistic, and find the P-value for the sample. State your conclusions about the claim.
The claim is that for 8 AM body temperatures of males, the mean is less than 98.6°F. The sample size is n = 36 and the test statistic is t= -3.675. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a significance level of 0.01. State the null and alternative hypotheses. Ho: HV H₁: p V (Type integers or decimals. Do not round. Do not include the degree symbol in your answer.) The test statistic is. (Round to two decimal places as needed.) The P-value is. (Round to three decimal places as needed.) Based on the P-value, there ▼sufficient evidence at a significance level of 0.01 to G ▼the claim that for 8 AM body temperatures of males, the mean is less than 98.6°F.
Suppose 200200 subjects are treated with a drug that is used to treat pain and 5454 of them developed nausea. Use a 0.100.10 significance level to test the claim that more than 2020% of users develop nausea. Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. Upper H 0H0: pequals=0.200.20 Upper H 1H1: pless than<0.200.20 B. Upper H 0H0: pequals=0.200.20 Upper H 1H1: pnot equals≠0.200.20 C. Upper H 0H0: pequals=0.200.20 Upper H 1H1: pgreater than>0.200.20 D. Upper H 0H0: pgreater than>0.200.20 Upper H 1H1: pequals=0.200.20 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is nothing. (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is nothing. (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test.…

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