College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Solve it correctly please. Iarrow_forwardAn object is placed in front of a converging lens with a radius of curvature of 4.88 cm. An image is formed 12.9 cm from the object. Calculate how far is the lens from the object if the image is virtual (b) How far is image from the lens? cm mm Is the image upright or inverted, and is the image magnified or smallified? Draw the ray-diagram to confirm your result prediction. A. Upright B. Invertedarrow_forwardIn the figure below, a diverging lens and concave spherical mirror are positioned along an optical axis, with an object half way between the two. The distance between the lens and mirror is d = 23.7 cm. The magnitude of the mirror's radius of curvature is 20.5 cm, and the lens has a focal length of flens = -18.4 cm. Lens Object Mirror I (a) Considering only the light that leaves the object and travels first toward the mirror, locate the final image formed by this system. (Give the magnitude of the image distance in cm, and select its location with respect to the lens.) image distance image location Apply the mirror equation to find the image formed by the mirror, which serves as an object for the lens. Then apply the thin-lens equation. cm to the right of the lens (b) Is this image real or virtual? O real O virtual (c) Is it upright or inverted? Ⓒupright O inverted (d) What is the overall magnification? Xarrow_forward
- A converging mirror has the focal length of 15 cm. For the object distance of 25cm draw the ray diagram and find the image distance and magnification. Describe the properties of the image.arrow_forwardA magnifying lens has a focal length of 25 cm. A coin is brought to 20 cm from the magnifying lens. What distance from the lens, di, does the image form at? What is the magnification, M? What are the image properties?arrow_forwardSuppose you have a concave mirror as shown in the image below. If h = 1.28m is the height of an object (really the displacement of the top of the object from the axis) and h' = 4.91m is the height of the image, what is the magnitude of the transverse magnification (in units of meters)? Object Imagearrow_forward
- A spherical concave lens has a focal length of 25 cm, and an object is placed 20 cm from the lens. Draw a ray diagram. estimate image distance ________ cmarrow_forwardYou are trying to photograph a bird sitting on a tree branch, but a tall hedge is blocking your view. However, as the drawing shows, a plane mirror reflects light from the bird into your camera. For what distance must you set the focus of the camera lens in order to snap a sharp picture of the bird's image? Number i Units 4.3 m -2.1 mi 3.7 m-arrow_forwardMinimum focal length of your eye Each of your eyes has a lens in it. This lens can change its shape and hence its focal length. By changing the focal length you are able to focus on an object based on how far away it is from you. For this problem you will determine the minimum focal length of your eye. A) Hold an object out in front of you at arm's length. Close one eye and bring the object towards your eye and determine how close it can be to your eye and still be in focus. 25 cm ✓ B.) The average human eye has an image distance of 1.7 cm. In other words, it is 1.7 cm from the lens in your eye to the retina. Using this information and your answer to (A), determine the minimum focal length of your eye. Also determine the magnification for this situation. min 6 x Units are required for this answer. M = 8 X C.) The lens in your eye creates an image. It is this image that the rods and cones in our eye actually detect. Regarding the image your lens created when finding the minimum focal…arrow_forward
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