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College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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![If the distance of the image from the lens (di) is negative. The image is considered to be...
imaginary
real
objective
virtual](https://content.bartleby.com/qna-images/question/ab8e90de-1834-4897-8d02-45bfaff51002/7244b19b-6f07-49ac-bd41-b1698de13e20/52tha9f_thumbnail.png)
Transcribed Image Text:If the distance of the image from the lens (di) is negative. The image is considered to be...
imaginary
real
objective
virtual
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- Needs Complete typed solution with 100 % accuracy.arrow_forwardAnobiect 5.0cm tall is 50.0cm infront of a lenswith 25cm ocal bength diver ging lensith 25cm focal leneth Is the image real or virtheal? the imes How far is Hhe irege noth 7. from Hhe lens? or inverted2 imeage Is the im ege Haw high is Hie image 15arrow_forwardA 2 cm high object is viewed through a diverging lens with a -12 cm focal length. If the object is 8cm from the lens, then realtive to the lens where is the image and what is its height?arrow_forward
- Needs Complete typed solution with 100 % accuracy.arrow_forwardA thin plastic lens with index of refractionn = 1.69 has radii of curvature given by R, = -11.5 cm and R, = 30.0 cm. HINT (a) Determine the focal length in cm of the lens. -12.05 cm (b) Determine whether the lens is converging or diverging. O converging O diverging Determine the image distances in cm for object distances of infinity, 7.00 cm, and 70.0 cm. (c) infinity -12.05 By the sign conventions for thin lenses, the negative image distances indicate the images are formed in front of the lens (on the same side as the object). cm (d) 7.00 cm cm (e) 70.0 cm cmarrow_forwardA compound microscope is made from an objective lens of focal length fo = 8 mm, andan eyepiece of fe = 12 mm. The objective lens is moved close to the object so that anintermediate image is formed 20 cm above the objective lens; then the eyepiece is set atits own focal length above the intermediate image, forming a virtual image at infinity forthe user’s eye. If the object is 0.15 mm in diameter, calculate the following, taking care todefine symbols used:i) The required distance of the objective lens above the object.ii) The diameter of the intermediate image.iii) The angular size of the image to the user’s eye.iv) The system angular magnification, defined as the angular size in (iii) divided by theangle subtended by the object to the naked eye from a distance of 25 cm.arrow_forward
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