// The language is c++ //please explain step by step By using vector handle dynamic, and for loop to print this message separately in each line. "This is C++ code with no commas semicolons of fullstops:;

NOTE: - To clearly demonstrating the concept, the size of the vector is printed at multiple places.

EXPLANATION: -

Defining Vector Dynamically: -

vector<string>* myVector = new vector<string>(5);

• The above line dynamically creates and initializes the vector named myVector with 5 empty strings.
• Right now myVector is already having 5 elements.
• Vector is dynamic in nature, it automatically increases its size when more elements are added to it.
• The size function on myVector gives the current size of the vector. Since it is a pointer, so arrow pointer is used to access the method
  • cout<<"vector size: "<< myVector->size() <<endl;
• Any push_back operation will result in an increment in the size of the vector named myVector.

push_back function: -

• This function adds elements at end of the vector, and each operation increments the vector size by 1.
  • myVector->push_back(message);//message is added at index 5
  • Vector also follows zero-based indexing.
• A total of 5 push_back operations are performed.
• Hence, the vector size becomes 10 now.

Now vector contains 5 empty strings, and 5 messages, a total of 10 elements.

Displaying the vector: -

• The vector elements are printed using for loop which runs from index 0 till the size of the vector - 1 that is 9.
• To access the element of the vector, dereferencing is required, since it is a pointer.
  • First, the vector variable myVector is dereferenced, then the element present at the index variable i is stored in variable myStringusing the rectangular brackets.
    • string myString = (*myVector)[i];
• Initially, there are five empty strings, so to prevent printing the empty strings, if the condition is applied, only if the string is not empty, it is printed on the console.