MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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The joint probability distribution of the number X of cars and the number Y of buses per signal cycle at a proposed left-turn lane is displayed in the accompanying joint probability table.
y
P(x, y)
1
2
0.010
0.015
0.025
1.
0,020
0.030
0.050
0.050
0.075
0.125
3
0.060
0.090
0.150
0.040
0.060
0.100
5
0.020
0.030
0.050
(a) What is the probability that there is exactly one car and exactly one bus during a cycle?
(b) What is the probability that there is at most one car and at most one bus during a cycle?
(c) What is the probability that there is exactly one car during a cycle? Exactly one bus?
P(exactly one car) =
P(exactly one bus) =
(d) Suppose the left-turn lane is to have a capacity of five cars and one bus is equivalent to three cars. What is the probability of an overflow during a cycle?
(e) Are X and Y independent rv's? Explain.
O Yes, because p(x, y) = px(x)•PylY).
O Yes, because p(x, y) # P(x) Py(Y).
O No, because p(x, y) = P(x)•Py(Y).
O No, because p(x, y) # Px(x) Py(Y).
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Transcribed Image Text:The joint probability distribution of the number X of cars and the number Y of buses per signal cycle at a proposed left-turn lane is displayed in the accompanying joint probability table. y P(x, y) 1 2 0.010 0.015 0.025 1. 0,020 0.030 0.050 0.050 0.075 0.125 3 0.060 0.090 0.150 0.040 0.060 0.100 5 0.020 0.030 0.050 (a) What is the probability that there is exactly one car and exactly one bus during a cycle? (b) What is the probability that there is at most one car and at most one bus during a cycle? (c) What is the probability that there is exactly one car during a cycle? Exactly one bus? P(exactly one car) = P(exactly one bus) = (d) Suppose the left-turn lane is to have a capacity of five cars and one bus is equivalent to three cars. What is the probability of an overflow during a cycle? (e) Are X and Y independent rv's? Explain. O Yes, because p(x, y) = px(x)•PylY). O Yes, because p(x, y) # P(x) Py(Y). O No, because p(x, y) = P(x)•Py(Y). O No, because p(x, y) # Px(x) Py(Y). Need Help? Watch It Read It MacBook Pro
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