I just need help drawing the KINEMATIC DIAGRAM and the GRAPHS (v-a, a-s, s-t, v-t, v-t, or a-t) if applicable. The jet plane starts from rest at s = 0 and is subjected tothe acceleration shown. Suppose that s' = 1200 ft(Figure 1)Part ADetermine the speed of the plane when it has traveled 1200 ftExpress your answer to three significant figures and include the appropriate units.ftv = 387SubmitPrevious AnswersFigure1 of 1v CorrectPart Ba (ft/s?)How much time is required for it to travel 1200 ft ?Express your answer to three significant figures and include the appropriate units.7550t' = 5.83 sSubmitPrevious Answerss (ft)Correct

Answered: The jet plane starts from rest at s = 0…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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I just need help drawing the KINEMATIC DIAGRAM and the GRAPHS (v-a, a-s, s-t, v-t, v-t, or a-t) if applicable.

The jet plane starts from rest at s = 0 and is subjected to
the acceleration shown. Suppose that s' = 1200 ft
(Figure 1)
Part A
Determine the speed of the plane when it has traveled 1200 ft
Express your answer to three significant figures and include the appropriate units.
ft
v = 387
Submit
Previous Answers
Figure
1 of 1
v Correct
Part B
a (ft/s?)
How much time is required for it to travel 1200 ft ?
Express your answer to three significant figures and include the appropriate units.
75
50
t' = 5.83 s
Submit
Previous Answers
s (ft)
Correct

Expert Solution

Step 1

$G i v e n, S' = 1200 f t u = 0, x = 0 (A) S i n c e w e k n o w t h a t w o r k d o n e = f . d s = m . (a^{\to} d s^{\to}) = m (A r e a u n d e r c u r v e) A c c o r d i n g t o w o r k e n e r g y t h e o r e m w_{n e t} = K E_{f} - K E_{i} m \times \frac{1}{2} \times (75 + 50) \times 1200 = \frac{1}{2} \times m \times {v_{f}}^{2} {v^{2}}_{f} = 1.5 \times 10^{5} v_{f} = 387.3 f t / s e c (B) Q = v \frac{d v}{d s} = 75 - \frac{25}{1200} s \int v . d v = \int (75 - \frac{25}{1200} 5) d s \frac{v^{2}}{2} = 75 s - \frac{5^{2}}{46} \times \frac{1}{2} + c ∴ v = 0 a t s = 0 c = 0 v^{2} = 1500 - \frac{5^{2}}{48} v = \sqrt{150 s - \frac{5^{2}}{48}}$

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