the Imagine a right angle triangle with two equal sides of 10 cm. Two equal charges of +10μC are placed in the vertices corresponding to the 45° angles. A negative, -20μC charge is placed at the 90° vertex. Find the electric field in the middle hypotenuse. You need to provide the magnitude of the field and the direction. For the direction use the angle between the electric field and the hypotenuse (the one less than 90°). ▾ Part A - What is the magnitude of the field at the point in the midle of the hypothenuse? ? Value Units Submit Request Answer ▸ Part B. What is the angle between the total field and the hypothenuse? (If the angle is not 90 degress, give the angle which is less than 90 degrees)

the Imagine a right angle triangle with two equal sides of 10 cm. Two equal charges of +10μC are placed in the vertices corresponding to the 45° angles. A negative, -20μC charge is placed at the 90° vertex. Find the electric field in the middle hypotenuse. You need to provide the magnitude of the field and the direction. For the direction use the angle between the electric field and the hypotenuse (the one less than 90°). ▾ Part A - What is the magnitude of the field at the point in the midle of the hypothenuse? ? Value Units Submit Request Answer ▸ Part B. What is the angle between the total field and the hypothenuse? (If the angle is not 90 degress, give the angle which is less than 90 degrees)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Two charges q1= +5 μC and q2= +8.5 μC are separated by a distance of 15 cm. Point Pis located along the line segment joining the two charges. How far is point Pfrom q1, if the magnitude of the electric field at point Pdue to the two charges is equal to zero?Draw a sketch of the problem and label appropriately
A small rubber sphere has a mass of 3.64 g and a charge of -18.6 µC. It levitates, motionless, when placed in a uniform electric field perpendicular to the ground. What is the magnitude of the electric field (in N/C)? N/C What is the direction of the electric field? O upward O downward O east west
Two equal positive charges (10 μC) are arranged at the base of an equilateral triangle of sides 20 cm. What is the electric field at the top vertex of the triangle? What is the direction of the electric field?
2 m P 1 m 92 -2m -Im 1m 2m Two point charges lie on the x-axis (see figure above) where q1 = -6.6nC and 92 = 3.7nC. What is the direction (angle in degrees) of the electric field due to 91 at point P? Measure the angle from the +x-axis counterclockwise. %3D +
A point charge q = -8.0 x 10* C is placed at the origin. Calculate electric field at a point 2.0 m from the origin on the z-axis.
In a rectangular coordinate system a positive point charge q = 6.00 x 10-9 C is placed at the point x = +0.150m, y = 0, and an identical point charge is placed at x = -0.150m, y = 0. Find the x- and y-components, the magnitude, and the direction of the electric field at the origin. (with precise solution please) A. Ex = 129N/C and Ey = -510N/C with direction of 284 degrees counterclockwise from +x axis B. Ex = 2663.1 N/C and Ey = 0 to the +x direction C. Ex = 0 and Ey = 0 D. none of the above
Three identical charges (q = -7.0 μC) lie along a circle of radius 3.9 m at angles of 30°, 150°, and 270°, as shown in the figure below. What is the resultant electric field at the center of the circle? 9 N/C 270° 150° 30°
The point charges in the figure below are located at the corners of an equilateral triangle 25.0 cm on a side, where q, = +19.0 µC and q. = -5.70 µC. (Assume that the +x-axis is directed to the right.) la (a) Find the electric field at the location of q.. magnitude N/C direction ° (counterclockwise from the +x-axis) (b) What is the force on given that 9a = +1.50 nC? magnitude N direction (counterclockwise from the +x-axis)
A 4.1 MC point charge is placed on the x-axis at the point X₁ = -22.5m. A second, 2.7-MC point Charge is placed on the x-axis at the point X₂ = 10.3m. What is the x-component of the net electric field (in N/C) at the origin? (Remember that vector components can be positive or negative) N/C
The figure below shows a dipole. If the positive particle has a charge of 40.1 mC and the particles are 3.02 mm apart, what is the electric field at point A located 2.00 mm above the dipole's midpoint? (Express your answer in vector form.) N/C E = A d/2 y d/2 X
A 6 µC charge q1 located at the origin cm creates an electric field that fills all of space. A -8 µC charge q2 is brought to the point cm. The 6 µC charge is returned but now the -8 µC charge is moved to cm. What is the new net force extered on q2? Answer as a vector in Newtons.
Three charges are on the plane (x,y) as reported on the picture. The two charges q on the x-axis are equal and at distance of 8 cm from the origin. The charge on the y-axis is negative and 3q and it is at 16 cm from the origin. Determine the x component of the electric field at the point P (0,5) cm. q P -39 q