the Imagine a right angle triangle with two equal sides of 10 cm. Two equal charges of +10μC are placed in the vertices corresponding to the 45° angles. A negative, -20μC charge is placed at the 90° vertex. Find the electric field in the middle hypotenuse. You need to provide the magnitude of the field and the direction. For the direction use the angle between the electric field and the hypotenuse (the one less than 90°). ▾ Part A - What is the magnitude of the field at the point in the midle of the hypothenuse? ? Value Units Submit Request Answer ▸ Part B. What is the angle between the total field and the hypothenuse? (If the angle is not 90 degress, give the angle which is less than 90 degrees)

the Imagine a right angle triangle with two equal sides of 10 cm. Two equal charges of +10μC are placed in the vertices corresponding to the 45° angles. A negative, -20μC charge is placed at the 90° vertex. Find the electric field in the middle hypotenuse. You need to provide the magnitude of the field and the direction. For the direction use the angle between the electric field and the hypotenuse (the one less than 90°). ▾ Part A - What is the magnitude of the field at the point in the midle of the hypothenuse? ? Value Units Submit Request Answer ▸ Part B. What is the angle between the total field and the hypothenuse? (If the angle is not 90 degress, give the angle which is less than 90 degrees)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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