Four identical charged particles (q = +10.3 µC) are located on the corners of a rectangle as shown in the figure below. The dimensions of the rectangle are L = 63.0 cm and W = 14.2 cm. Four identical positive charges, each of charge q, are on the corners of a rectangle in the x y coordinate plane. The locations of the charges are as follows. (0, 0) (L, 0), where L > 0 (L, W), where W > 0 (0, W) (a) Calculate the magnitude of the total electric force exerted on the charge at the lower left corner by the other three charges.  N

The figure below shows three positively charged particles at three corners of a rectangle. The particle at upper left has a charge q1 = 4.00 nC, the one at the lower left has a charge of q2 = 5.00 nC,and the one at lower right has a charge q3 = 6.00 nC. The rectangle's horizontal side has length x = 5.00 cm and its vertical side has length y = 3.50 cm. Three positive charges lie at three of the corners of a rectangle of horizontal side length x and vertical side length y < x. An charge labeled q1 is at the upper left corner. A charge labeled q2 is at the lower left corner. A charge labeled q3 is at the lower right corner. (a)What is the electric potential (in V) at the upper-right corner of the rectangle? (Assume the zero of electric potential is at infinity.) ______V (b)What would be the potential (in V) at the upper-right corner if the charge q2 at lower left was−5.00 nC instead? _____V

Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are  A = 2.10 pC, B = 6.90 pC, and C = −3.80 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 ✕ 10−12 C.) magnitude: __ N/C direction: __ degrees counterclockwise from the +x-axis If the charge of cell A were doubled, how would the electric field at cell A change? The field would be unchanged. The magnitude of the field would be halved.     The magnitude of the field would be doubled. The magnitude of the field would be quadrupled.

Two charges q1 = +4.35 µC and q2 = +6.25 µC are separated by a distance of 13.17 cm. Point P is located along the line segment joining the two charges. How far is P (in cm) from q1, if the magnitude of the electric field at P due to the two charges is equal to zero? Express your answers accurate to two decimal places.