The histogram shows the reviewer ratings on a scale from 1 (lowest) to 5 (highest) of a recently published book. Reviewer Ratings 0.5- 0.4- 0.444 (a) Find the mean, variance, and standard deviation of the probability distribution. (b) Interpret the results. 0.3- 0.214 0.249 0.2- 0.14 0.022 0.01 0.071 Rating (a) The mean is (Type an integer or a decimal. Do not round.) The variance is. (Round to two decimal places as needed.) The standard deviation is (Round to two decimal places as needed.) (b) Interpret the results. Select all that apply. O A. The typical rating deviates from the mean by about 4. O B. The average rating for the book is approximately 4. O C. The typical rating deviates from the mean by about 1. O D. The average rating for the book is approximately 1. Kuigegoid

Use the probability distribution to complete parts​ (a) and​ (b) below. Activities    Probability0                  0.0611                  0.1242                  0.1663                   0.1674                   0.2035                    0.1196                    0.1167                    0.044 ​(a) Find the​ mean, variance, and standard deviation of the probability distribution (b) Interpret the results.

The histogram shows the reviewer ratings on a scale from 1 (lowest) to 5 (highest) of a recently published book. (a) Find the mean, variance, and standard deviation of the probability distribution. (b) Interpret the results. (a) The mean is 4.005. (Type an integer or a decimal. Do not round.) The variance is (Round to two decimal places as needed.) Probability 0.5- 0.4 0.3- 0.2- 0.1- 0.0¹ 0.019 Reviewer Ratings 0.082 0.218 0.237 3 Rating 4 0.444

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Use the probability distribution to complete parts (a) and (b) below. The number of school-related extracurricular activities per student 6 7 0 1 2 3 Activities 4 5 Probability 0.059 0.123 0.164 0.176 0.212 0.126 0.085 0.055 (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is (Round to one decimal place as needed.)

Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 1 2 4 Probability 0.264 0.290 0.240 0.148 0.042 0.016 ..... (a) Find the mean, variance, and standard deviation of the probability distribution.

The diameters of ball bearings are distributed normally. The mean diameter is 53 millimeters and the variance is 25. Find the probability that the diameter of a selected bearing is greater than 48 millimeters. Round your answer to four decimal places. Answer Tables Normal Table - to-z Z -2.8 -2.7 -2.6 -2.5 -2.4 -2.3 -1.9 -1.8 0.09 0.08 0.07 0.06 0.05 0.04 0.03 0.02 0.01 0.00 -3.4 0.0002 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 -3.3 0.0003 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.0005 0.0005 0.0005 -3.2 0.0005 0.0005 0.0005 0.0006 0.0006 0.0006 0.0006 0.0006 0.0007 0.0007 -3.1 0.0007 0.0007 0.0008 0.0008 0.0008 0.0008 0.0009 0.0009 0.0009 0.0010 -3.0 0.0010 0.0010 0.0011 0.0011 0.0011 0.0012 0.0012 0.0013 0.0013 0.0013 -2.9 0.0014 0.0014 0.0015 0.0015 0.0016 0.0016 0.0017 0.0018 0.0018 0.0019 0.0019 0.0020 0.0021 0.0021 0.0022 0.0023 0.0023 0.0024 0.0025 0.0026 0.0026 0.0027 0.0028 0.0029 0.0030 0.0031 0.0032 0.0033 0.0034 0.0035 0.0036 0.0037 0.0038 0.0039…

The probability distribution below is for the random variable X = the number of credits taken during the fall semester by a randomly selected student at a large university.   Calculate the mean of X. Round to the hundredths place. Credits 14 15 16 17 Probabiblity 0.05 0.65 0.20 0.10

Use the probability distribution to complete parts​ (a) and​ (b) below.   The number of​ school-related extracurricular activities per student Activities 0 1 2 3 4 5 6 7   Probability 0.061 0.122 0.164 0.178 0.211 0.127 0.082 0.055   (a) Find the​ mean, variance, and standard deviation of the probability distribution.     ​(b) Interpret the results.   The mean is ______so the average student is involved in_____The standard deviation is_____so the typical number of activities per student deviates_______

Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 1 2 3 4 5 Probability 0.259 0.293 0.244 0.150 0.037 0.017 ... (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is (Round to one decimal place as needed.) The variance is (Round to one decimal place as needed.) The standard deviation is (Round to one decimal place as needed.) (b) Interpret the results. The mean is , so the average batch of 1000 machine parts has The standard deviation is so the typical number of defects in a batch of 1000 (Round to one decimal place as needed.)