The high-level function strcpy copies the character string src to the character string dst. void strcpy(char dst[], char src[]) { int i = 0; do { dst[i] = src[i]; } while (src[i++]); } Q1.1 Implement the strcpy function in MIPS assembly code. Use $se for i. A Please select file(s) Select file(s)
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![Q1
The high-level function strcpy copies the character string src to the character string dst.
void strcpy(char dst[], char src[]) {
int i = 0;
do {
dst[i]
} while (src[i++]); }
= src[i];
Q1.1
Implement the strcpy function in MIPS assembly code. Use $se for i.
Please select file(s)
Select file(s)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5d6a01d3-82e5-4350-87dd-6f226ff184e6%2F60788497-d875-43f3-bf56-14842375c69d%2F4yyfnb_processed.jpeg&w=3840&q=75)
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- 6. The high-level function strcpy copies the character string src to the character string dst. // c code int i = 0; do { dst[i] = src[i]; } while (src[i++]); Write the code snippet in ARM assembly. Use R4 for i. Assume that the base addresses of dst and src are held in R1 and R2Coding Hacks In C Program, given an integer, write a detailed algorithm/code to find the square of the given integer without using a multiplication or division operator. Also, the use of the pow() [power] function is not allowed./* Javascript! Create a function that run anot function after a delay. Arguments: callback: the function to execute after the delay delay: number of milliseconds to wait data: the one (and only) argument to pass to the callback */ const callAfter = function(callback, delay, data) { // IMPLEMENT ME
- using c++ .. - Implement a function string convertToBinary(int) that uses a stack to convert a decimal number to a binary number returned as a bit string.Example input: 218. Output: 11011010Debug my C code and translate the small code into assembly language. Thank you! #include <stdio.h> #include <stdlib.h> int Length = 4; int Seq[] = {17, 34, 51, 68}; int main() { int Next = 0; //Sets value for Next. int i = 1; // sets initial value for i. while (i != 4){ //condition for while loop. Next = Next + 17; //adds integer value to Next. i++; //post increment for @param i. return Next; //returns value for Next. } // your program should use this print statement printf("The next integer in the sequence: %d\n", Next); return 0; }Convert this code to RISC-V 64 gcc assembly language #include <stdio.h> char inputText[] = "babibabbbiiibabibiba";char pattern[] = "bi";const int patternSize = 2;const int inputSize = 20; int main(){ int lps[patternSize]; lps[0] = 0; int len = 0; int i = 1, j = 0; while (i < patternSize) { if (pattern[i] == pattern[len]) { len++; lps[i] = len; i++; } else { if (len != 0) { len = lps[len - 1]; } else { lps[i] = 0; i++; } } } i = 0; while (i < inputSize) { if (pattern[j] == inputText[i]) { j++; i++; } if (j == patternSize) { printf("Found pattern at index %d \n", i - j); j = lps[j - 1]; } else if (i < inputSize && pattern[j] != inputText[i]) {…
- Electrical Engineering Consider a function called Vocals. This function has as parameter the starting address of a string of characters. The function calculates the number of times the 'a' character appears (in lowercase) in the string. In case of passing the mull string the function returns the value -1. In case the string does not have any 'a', the function returns 0. It is requested: 1. Program using the assembler 8086 the code of the Vocal function 2. Program using the ARM assembler the code of the Vocal functionInstruction: Explain the function of the program line by line thoroughly.Program: #include <iostream> using namespace std; //Swap functionvoid swap(int *xp, int *yp){ int temp = *xp; *xp = *yp; *yp = temp;} void selectionSort(int arr[], int n){ int i, j, min_idx; // One by one move boundary of // unsorted subarray for (i = 0; i < n-1; i++) { // Find the minimum element in // unsorted array min_idx = i; for (j = i+1; j < n; j++) if (arr[j] < arr[min_idx]) min_idx = j; // Swap the found minimum element // with the first element if(min_idx!=i) swap(&arr[min_idx], &arr[i]); }} //Function to print an arrayvoid printArray(int arr[], int size){ int i; for (i=0; i < size; i++) cout << arr[i] << " "; cout << endl;} int main(){ int x, n; cout << "Enter number of integers: "; cin >>n; int *arr = new int(n); for (int i = 0; i < n; i++) { cout << " Enter Integer No. " << (i + 1) << ": ";…include <bits/stdc++.h> using namespace std; int MSD(int n){ if(n == 0) return 0; int k = log10(n); int x = pow(10,k); int ans = n/x; return ans; } int main() { int n; cin >> n; cout << MSD(n).
- In Assembly language Write and test a function that removes the leading and trailing spaces from a string. The function has two parameters. The first parameter is the address of the original string. The second parameter is the address of a string that is almost a copy of the original string. The difference between the strings is that the first string may have leading or trailing spaces and the second string will not have leading or trailing spaces. Use the function Str_length to compute the length of the original string.2. Consider the two main variables: Number and N. Number is a 1024 byte variable. It represents a huge unsigned integer. N is a 4 byte variable. It represents the number of bits by which the number will be shifted. assenbly language Write an SHL1024 function that receives two parameters on the stack: the address of a number of 1024 bytes and a value giving by how many bits the number of 1024 bytes will be shifted towards the left. This function must act like an SHL but on a 1024 byte variable. On return, the content of the Number variable will be shifted to the left by the number of bits demand. On return, the values of the general registers and the EFLAGS should be the same as before the call to SHL1024XII. Reconstruct the following C code for this recursive function by looking at the assembly code. Fill in the blanks: unsigned myfunction2 (unsigned n) { if ( else { } .L9: _) return 1; return 1 + myfunction2( } my function2: testq jne .L9 %rdi, %rdi movq $1, %rax ret subq $8, %rsp shrq $2, %rdi call myfunction2 addq $1, %rax addq $8, %rsp ret