The height that a cartoon character starts from is 5.00 meters. The radius of the loop the loop is 1.75 meters. Do not need the mass of the character.  In order to clear the loop to make without falling off, the cartoon character must achieve a speed of at least 4.43 m/s at the top of the loop.  Can the character make the loop without falling off?

True or False

A 3200 kg coaster car rolls along the frictionless track shown. To safely make it through the loop there is a minimum speed the coaster must have at the top of the loop. At this speed the normal force of the track pushing downward on the coaster is zero. The radius of the circular loop is 14.1 meters. At the top of the loop of radius 14.0 m the force of gravity is the only force acting on the coaster. What is the magnitude of the coaster's acceleration at the top of the loop?

A small block with mass 0.0425 kg slides in a vertical circle of radius 0.450 m on the inside of a circular track During one of the revolutions of the block, when the block is at the bottom of its path, point A, the magnitude of the normal force exerted on the block by the track has magnitude 3 85 N. In this same revolution, when the block reaches the top of its path, point B, the magnitude of the normal force exerted on the block has magnitude 0575 N Part A How much work was done on the block by friction during the motion of the block from point A to point B Express your answer with the appropriate units. Writion 0.15 Submit → J Previous Answers Request Answer X Incorrect; Try Again: 2 attempts remaining Check your signs ?

A ball of mass 2.3 kg, at one end of a string of length L=4.5 m, rotates in a vertical circle just fast enough to prevent the string from going slack at the top of the circle. Assuming mechanical energy is conserved, the speed of the ball (in m/s) at the bottom of the circle is: m a. 10.50 Ob. 8.13 Oc. 9.39 Od. 14.85 Oe. 6.64

Consider two boxes initially at rest as shown, each of mass 5.0 kg, that are connected by a massless string over a pulley of radius 5.0 cm and rotational inertia equal to 4.0 x 10-3 kg·m². The coefficient of kinetic friction between the inclined surface and the box is 0.15. Find the speed of the boxes just after they have moved 1.0 m. Justify approach taken as you begin your solution. 30° m m

Q2: (a) A particle of mass m moves under the influence of the force F = a(sinwtî + coswtſ). If the particle initially at rest at the origin. Prove that work done at any time t is given by W = mw? =(1– coswt) and that the instantaneous power applied is - sinwt. ma? (b) Find the moment of inertia of a ring of radius a about an axis through its center.

In the game of tetherball, a 1.25-m rope connects a M = 0.850-kg ball to the top of a vertical pole so that the ball can spin around the pole as shown in the figure below. M 1.25 m 0 1) What is the speed of the ball as it rotates around the pole when the angle of the rope is 37.0° with the vertical? (Express your answer to three significant figures.) 1 S

A 2.0kg ball moves counterclockwise in a 0.75 m radius Vertical Circle. The Vt at the bottom is measured to be 7.0 m/s. What is the tension in the string at A, B, C, D? (See attachment)

the speed of the roller coaster, in meters per second, is 16.71. At the top of the loop if the radius of curvature is 15 m the downward acceleration of the car is 1.9g. The height of the loop is 14.15 m.   If the loop actually starts 6.5 m higher than your answer to the previous part (yet still reaches the top of the loop with the same velocity), how much energy, in joules, did it lose to friction? Its mass is 1400 kg.