The heat supplied is 500 J. The heat loss to the environment is 160 J. Step 2 Calculation: Write the expression for the work output from the heat engine. W=Q1-Q2 Here, W is the useful workout, Q1 is the supplied heat, and Q2 is the heat loss. Substitute, all known values in the above expression. W=400 J-160 J=240 J Thus, the useful work is 240 J. What is the efficiency of the heat engine in the preceding problem at top? a) 32% b) 54% c) 68%. d) 75% e) 175%

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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The heat supplied is 500 J.

The heat loss to the environment is 160 J.

Step 2

Calculation:

Write the expression for the work output from the heat engine.

W=Q1-Q2

Here, W is the useful workout, Q1 is the supplied heat, and Q2 is the heat loss.

Substitute, all known values in the above expression.

W=400 J-160 J=240 J

Thus, the useful work is 240 J.

 

What is the efficiency of the heat engine in the preceding problem at top?

a) 32%

b) 54%

c) 68%.

d) 75%

e) 175% 

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