MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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The Greater Pittsburgh Area Chamber of Commerce wants to estimate the
time workers who are employed in the downtown area spend getting to work. A
sample of 15 workers reveals the following number of minutes spent traveling.
29 38 38 33 38 21 45 34
40 37 37 42 30 29 35
a. Develop a 95 percent confidence interval for the population mean. Interpret the
result.
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- The accompanying dala gives the results of a survey on the number of hours spent online per week on a certain social networking website. Determine if the mean number of hours spent online per week is the same for males as it is for females. Assume that the population variances are unequal Click the icon to view the social media survey data. Is there sufficient evidence at the 0.05 level of significance that the mean number of hours spent online per week is the same for males as it is for females? Determine the null hypothesis, Ho, and the alternative hypothesis, H₁. Let females be population 1 and males be population 2. Survey data Ho H₁ (Type integers or decimals. Do not round.) Gender Female Hours online/week Gender Hours online/week D 4 Male Female 11 Male Female 9 Male Female 8 Male Female 7 Male Female 13 Male Female 2 Male Female 6 Male Female 2 Male Female 6 Male Female 7 Make Female 3 Male Female Female Female Female Female Female Female Female 46021337 Mole 0653T50478145 8…arrow_forward4. At private college the achievement test is used for advanced study placement. Counselors selected a random sample of 144 students from the college and scored their tests by hand before sending them in for computer processing. For this sample, the mean was 450 and s = 29. Construct a 98% confidence interval for the mean.arrow_forwardAn apartment hunter is shopping for either a one-bedroom or two-bedroom apartment in varying apartment buildings. She wants to estimate the additional amount she would have to pay, on average, for a two-bedroom apartment versus a one-bedroom apartment. The table shows the prices, in dollars, for one- and two-bedroom apartments from the nine buildings she visited. A 95% confidence interval for the true mean difference between two-bedroom and one-bedroom apartments for apartment buildings like the ones in the sample was (255.93, 508.51). A friend of the apartment hunter tells her to expect to pay about $500 more per month for a two-bedroom apartment than for a one-bedroom apartment. Does the confidence interval provide evidence for the friend’s claim? A. No, the confidence interval does not contain 0, so the friend’s claim is not plausible. B. No, the confidence interval contains many more numbers below 500 than above 500, so it is unlikely that the friend’s assertion is correct. C.…arrow_forward
- In a random sample of 2500 men being treated for obesity, the mean total cholesterol level is 175 with a standard deviation of 25. Construct a 95% confidence interval around the mean and interpret it. Use the context of the question please.arrow_forwardPlease answer the following: You can use the graphing calculator-just explain how to input into calculator. A tire manufacturer beleives that the tread life of its snow tires can be described by a normal model with a mean of 32,000 miles and standard deviation of 2,500 miles. a) If you buy a set of these tires, would it be reasonable for you to hope that they last 40,000 miles? Explain. b) What proportion of these tires can be expected to last less than 30,000 miles? c) What proportion of these tires can be expected to last between 30,000 and 35,000 miles? d) Estimate the IQR of the tread lives. e) In planning a marketing strategy, a local tire dealer wants to offer a refund to any customer whose tires fail to last a certain number of miles. However, the dealer does not want to take too big a risk. If the dealer is willing to give refunds to no more than 1 of every 25 customers, for what mileage can he be guaranteed these tires to last?arrow_forwarddo the last one pleasearrow_forward
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