The generator convert from PV to PQ if the active power of the generator exceed the * maxinum and minimum limits between the maximum and mimium limit equal to the load power O Non of them
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A: Given statement When the load on a series generator is increased, then the flux produced will…
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Q: Q31. If the no load voltage of a certain generator is 210 V and the rated voltage is 200 V, then the…
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Q: What will be the value of the twiddle factor: W42
A: In this case, the value of the twiddle factor W42 is to be determined.
Q: np = 100 turns, how many turns are required for secondary winding nạ? A 10 B 100 1000 10^4
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Q: A d.c. generator running at 25 rev/s, generates an e.m.f. of 150 V. Determine the percent- age…
A: Given data, Speed, N1=25 rev/s = 25×60=1500 RPMN2=20 rev/s=20×60 = 1200 RPM EMF of generator E1=150…
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A: The solution is given below
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Q: When the load on a series generator is increased, then the flux produced will increase in direct…
A: The given statement is true. The explanation is provided below.
Q: Two DC shunt generators A and B are rated at a 100 and 150kW at 110V respectively. Their external…
A: In this question, we need to determine the terminal operating voltage if two machines are operated…
Q: When the load on a series generator is increased, then the flux produced will be decreased. Select…
A: According to question we have to discuss about change in flux.
Q: A 6-pole lap wound generator has 900 conductors. The e.mf induced per one tur being 3 V. the…
A: Given lap connected , So, No. of poles = No. of parallel paths = 6 Given voltage per turn = 3 volts…
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A: The explanation is as follows.
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A: Given: Number of poles in lap wound generator are doubled.
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Q: Two 220V generators operate in parallel. One machine has a terminal voltage of 270 V on no-load and…
A: Given: G1: G2:V1=220 V…
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A: Current and flux are in phase .here pase difference is zero degrees
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Q: The DC voltage is generated in the Field winding of DC Generator. Select one: True False
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Q: 1. Ifa field excitation of 10 A in a certain alternator gives a current of 150 A on short-circuit…
A: By synchronous impedance method: ZS=VtO.C.CIscS.C.CZS=900150ZS=6Ω
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Q: imary winding is connected o be applied at normal freq rough it when the secondary conner loss
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A: 10) From the above question the data is given below: C=30 μFL=0.155 HV=120 VF=60 Hz
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A: In this question we need to verify the given statement is true or false
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Q: Figure below shows a power system. The rating of generators and transformers are:G1:25MVA, 6.6KV,…
A: base value 30 KVA and 6.6 KV=0.03 MVAXpu(new)= Xpu(old) ×(MVAnew)(MVAold)×(KVoldKvnew)2
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A: Given Generator voltageE=12 vInternal resistancer=0.05 ΩTwo loads in parallelLoad-1 takes current…
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Q: JULI UWI3ICI anu sub transient cond The most popularly used method to represent the generator, while…
A: here question is the most popular method of representing The generator
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- The reactance of a generator is given as 0.1 pu based on the generator of 17 KV, 300 MVA. Determine the pu reactance on a base of 17 KV, 250 MVA. New pu reactance is.......In the system shown in Figure 1, the transformers are connected star-star with both star points grounded and the generators are connected in star with thier star points grounded. The system base is 15 MVA. The transformers all have reactances of 0.04 p.u. on this 15 MVA base. The reactances of all other elements are given in Table 1 (in 2) and the voltage levels are given in Table 2. p.u. G1 p.u. T1 jö Per-Unit Convert all values to p.u. on a 15 MVA base. Xa= p.u. Xc₂= XL = V BABE G1 2 X 9 T3 Figure 1: A section of the distribution system T1 L Table 1: Sequence reactances (2) 3 G1 L G2 0.3 0.59 0.01 4 L 9/10 10 Fault Voltage What is the voltage at bus 3 (in Volts) after the fault has occurred? Vp= V T2 5 T2 34 10/4 Table 2: Voltage bases (kV) G2 4 T3 10/9 | G2 Fault Current A three-phase fault with a fault reactance of 0.01 p.u. occurs at bus 3. Calculate the fault current flowing at the fault point in KA. Ip=-j KA SoThe reactance of a generator is given as 0.25 per-unit based on the generator’s of 18 kV, 500 MVA. Find its per-unit reactance on a base of 20 kV, 100 MVA. a. 0.0505 b. 0.0605 c. 0.0405 d. 0.0606
- The p.u. impedance value of an alternator corresponding to base values of 13.2 kV and 30 MVA is 0.2 p.u. Then the p.u. impedance value of an alternator for the new base values of 13.8 kV and 50 MVA is......3 X 0.1 1 2 XL = 0.2 to Eato oto O X = 0.1 X = 0.1 Above is the one-line diagram of a simple power system. Each generator is represented by an emf behind the subtransient reactance. All impedances are expressed in per unit on a common base. All resistances and shunt capacitance are neglected. The generators are operating on no load at their rated voltage with their emfs in phase. A symmetrical fault occurs at bus 1 through a fault impedance Z, =j0.08 per unit. a) Using Thevenin's Theorem, determine the impedance to the point of fault and the fault current in per unit. (2 Marks) b) Find the bus voltages and line currents during the fault. (2 Marks)Q5/B: Explain delta-star connection of 3 ph transformers. What its advantages and disadvantages?
- 6.5% ans ex A so kvA. 2o00/20 V, So He single-phase transformar has impedance drof of8% and resistance drop of 4%. Caleulate. The Requlation of the Thams former at full- Load o8 P.s Legging. also find The Power factor at which Voltage requlation will Be Zero. Sols 0.5 leading. s alculate The % Noltege Requlation af atransformar in w hich the Percantage resistance drof is 1% and Percentage dre is 6% when The Power fador is 0.8 lagging ) > unity aMS 38 % ans 1 % (シ→ 0.8 leading . amS - 2.2%A synchronous generator has been synchronized to an infinite grid of 13.8 kV and 60 Hz. The generator prime mover C/C is such that the no-load frequency is 62.5 Hz and the power slope is 1 MW/Hz. The AVR C/C (The reactive power against the terminal voltage C/C) is such that the zero reactive power voltage is 14.6 kV, while the slope is 0.4 MVAR/kV. Calculate: (a) the kVA loading of the generator and its power factor. (b) the settings of the prime mover and AVR such that the generator delivers 3 MW at 0.85 lagging power factor.What is the main direct cause of reactive power in AC system?A. Resistance of transmission linesB. Inductance and capacitance in the loadsC. Ideal transformer connected in the systemD. Power produced by generator
- The net cross section of a transformer is 20 square inches. The maximum fluxdensity is 11 kilogausses. The frequency is 60 Hz. If there are 1,000 turns in theprimary, determine the primary induced emf.What is phase angle of voltage induced in primary and secondary windings of transformers due to mutial flux? O Same Opposite Zero None of optionAlternator A (100 kVA, 3-f, 240 V, 60 Hz, 1800 rpm) is operating in parallel with alternator B (125 kVA, 3-f, 240 V, 60 Hz, 1800 rpm). The load of alternator A is 70 kW at 85% pf leading and the load of alternator B is 85 kW at 75% pf leading. Determine the pf of load.