The gel image below shows 7 alleles, let's call them 1-7 in order of size, with 1 being the largest and 7 being the smallest. Imagine the unlikely case that the 11 individuals represented in the gel image above were truly representative of the population. What is the frequency (f) of allele 6? Give your answer as a percentage, to one decimal place, do not include the % symbol.

In a population with two alleles at the R locus (R and r), the frequency of the genotype rr is 0.24. Assuming that the R locus is at Hardy-Weinberg equilibrium in this population, what is the frequency of heterozygotes (Rr)? Round and report your answer to the second decimal place (0.00). Your Answer:

In a lab population of mice, a locus affecting fur color has 2 alleles. The B allele produces brown fur, while the b  allele produces white fur. Heterozygote individuals (Bb) have beige fur. In a sample of 150 mice, 48  mice have white fur, and 13  have beige fur. What is the frequency of the B allele? Answer with two decimals precision (0.00).

A population of dragons or Varanus dragonus has two alleles B and P encoding for phenotypes blue and purple scales, is dominant over B. You have population of 345 individuals. PP = 100, BP; =90 , and BB = 155 . What is the frequency of the P allele? Please use and round to four decimal points.

please plug in 5 and 6 into the hardy weinberg equilibrium formula p2 + 2pq + q2 = 100 to calculate frequency thank you!

Pretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem.  So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations).  If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…

Consider an autosomal locus with alleles A and a. If the the allele frequencies are as follows Freq(A) = 0.4, Freq(a) = 0.6. , then what is the predicted frequency of heterozygous Aa individuals, assuming the population is in Hardy-Weinberg equilibrium? Freq(Aa) = ? Enter a number between 0 and 1, inclusive, for example 0.33

In a population with two alleles at the R locus (R and r), the frequency of the genotype rr is 0.10. Assuming that the R locus is at Hardy-Weinberg equilibrium in this population, what is the frequency of heterozygotes (Rr)? Round and report your answer to the second decimal place (0.00).