The gas phase production of Hydrogen lodide (HI) at 450°C and 2 atm is as shown below. The input stream contains 1 mole of Hydrogen (H2) and 1 mole of lodine (l2). The equilibrium constant (K) for this reaction is 25. H¿(g) + 1½(g) 2 HI(g) O Calculate the conversion of hydrogen. (i) Calculate the conversion of hydrogen when the pressure is 4 atm. (ii) Calculate the conversion of hydrogen when 1 mole of inert is present along with lodine at 2 atm.

Introduction to Chemical Engineering Thermodynamics
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Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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thermodynamic
The gas phase production of Hydrogen lodide (HI) at 450°C and 2 atm is as shown below. The
input stream contains 1 mole of Hydrogen (H2) and 1 mole of lodine (l2). The equilibrium
constant (K) for this reaction is 25.
H¿(g) + 1½(g) 2 HI(g)
O Calculate the conversion of hydrogen.
(i) Calculate the conversion of hydrogen when the pressure is 4 atm.
(ii) Calculate the conversion of hydrogen when 1 mole of inert is present along with lodine
at 2 atm.
(iv) Comment on the effect of pressure on conversion.
Given equations:
n, = no + 0,ɛ
K
%3D
nio-n
%3D
nio
Po
K =
%3D
K =
Po
Transcribed Image Text:The gas phase production of Hydrogen lodide (HI) at 450°C and 2 atm is as shown below. The input stream contains 1 mole of Hydrogen (H2) and 1 mole of lodine (l2). The equilibrium constant (K) for this reaction is 25. H¿(g) + 1½(g) 2 HI(g) O Calculate the conversion of hydrogen. (i) Calculate the conversion of hydrogen when the pressure is 4 atm. (ii) Calculate the conversion of hydrogen when 1 mole of inert is present along with lodine at 2 atm. (iv) Comment on the effect of pressure on conversion. Given equations: n, = no + 0,ɛ K %3D nio-n %3D nio Po K = %3D K = Po
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