The freezing point of benzene, C6H6, is 5.50 °C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene is DDT. A student dissolves 11.78 grams of DDT, C14H9 C15 (354.5 g/mol), in 252.1 grams of benzene. Use the table of boiling and freezing point constants to answer the questions below. Solvent Water Ethanol Chloroform Benzene Formula H₂O CH3 CH₂ OH CHCl3 C6H6 Diethyl ether CH3 CH2 OCH2 CH3 The molality of the solution is The freezing point of the solution is Kb (°C/m) Kf (°C/m) 0.512 1.86 1.22 1.99 3.67 2.53 2.02 m. °C. 5.12

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**Title: Determining the Freezing Point Depression of a Solution**

**Introduction:**
The freezing point of pure benzene, \( \text{C}_6\text{H}_6 \), is \( 5.50 \, ^\circ\text{C} \) at 1 atmosphere. When a nonvolatile, nonelectrolyte solute such as DDT (dichlorodiphenyltrichloroethane) dissolves in benzene, it causes the freezing point of the solution to lower. The task is to determine the molality and new freezing point of a benzene solution with DDT.

**Problem Statement:**
A student dissolves 11.78 grams of DDT (\( \text{C}_{14}\text{H}_9\text{Cl}_5 \); molar mass = 354.5 g/mol) in 252.1 grams of benzene. Using the provided table of boiling and freezing point constants, calculate:

1. The molality of the solution.
2. The freezing point of the solution.

**Data:**

| Solvent       | Formula           | \( K_b \, (^\circ\text{C/m}) \) | \( K_f \, (^\circ\text{C/m}) \) |
|---------------|-------------------|-------------------------------|-------------------------------|
| Water         | \( \text{H}_2\text{O} \)    | 0.512                         | 1.86                          |
| Ethanol       | \( \text{CH}_3\text{CH}_2\text{OH} \) | 1.22                          | 1.99                          |
| Chloroform    | \( \text{CHCl}_3 \)        | 3.67                          | 3.62                          |
| Benzene       | \( \text{C}_6\text{H}_6 \)        | 2.53                          | 5.12                          |
| Diethyl ether | \( \text{CH}_3\text{CH}_2\text{OCH}_2\text{CH}_3 \) | 2.02                          | —                             |

**Instructions:**

1. **Calculate the Molality (\( m \)) of the Solution:**
   - Use the formula:
     \[
     \text{molality} \, (
Transcribed Image Text:**Title: Determining the Freezing Point Depression of a Solution** **Introduction:** The freezing point of pure benzene, \( \text{C}_6\text{H}_6 \), is \( 5.50 \, ^\circ\text{C} \) at 1 atmosphere. When a nonvolatile, nonelectrolyte solute such as DDT (dichlorodiphenyltrichloroethane) dissolves in benzene, it causes the freezing point of the solution to lower. The task is to determine the molality and new freezing point of a benzene solution with DDT. **Problem Statement:** A student dissolves 11.78 grams of DDT (\( \text{C}_{14}\text{H}_9\text{Cl}_5 \); molar mass = 354.5 g/mol) in 252.1 grams of benzene. Using the provided table of boiling and freezing point constants, calculate: 1. The molality of the solution. 2. The freezing point of the solution. **Data:** | Solvent | Formula | \( K_b \, (^\circ\text{C/m}) \) | \( K_f \, (^\circ\text{C/m}) \) | |---------------|-------------------|-------------------------------|-------------------------------| | Water | \( \text{H}_2\text{O} \) | 0.512 | 1.86 | | Ethanol | \( \text{CH}_3\text{CH}_2\text{OH} \) | 1.22 | 1.99 | | Chloroform | \( \text{CHCl}_3 \) | 3.67 | 3.62 | | Benzene | \( \text{C}_6\text{H}_6 \) | 2.53 | 5.12 | | Diethyl ether | \( \text{CH}_3\text{CH}_2\text{OCH}_2\text{CH}_3 \) | 2.02 | — | **Instructions:** 1. **Calculate the Molality (\( m \)) of the Solution:** - Use the formula: \[ \text{molality} \, (
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