The freezing point depression of a solution is dependent on the number of particles in the solution, not the type of particles

Chemistry & Chemical Reactivity
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ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter13: Solutions And Their Behavior
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The freezing point depression of a solution is dependent on the number of particles in the solution, not the type of particles. If
0.1 moles of each of the following soluble ionic compounds, sodium phosphate, Na3PO4, and sodium chloride, NaCl, are
added to separate beakers containing 1 L of distilled water, which would have the lower freezing point? Explain.

Expert Solution
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Solution:- Given data:- 0.1 mole of Na3PO4 in 1 L water

0.1 mole of NaCl in 1 L water.

So, concentration(molality) of both compound is 0.1 m      [Because 1 L = 1 Kg water.]

Now, TF = i × KF × c

\Delta T_F = freezing point depression
K_F = cryoscopic constant (depends upon solvent)
c (concentration) = molality
i = Van't Hoff factor

 

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