The formula used to calculate a confidence interval for the mean of a normal population when n is small is the following.x + (t critical value)What is the appropriate t critical value for each of the following confidence levels and sample sizes? (Round your answers to two decimal places.)USE SALT(a) 95% confidence, n = 17(b) 90% confidence, n = 12(c) 98% confidence, n = 24(d) 90% confidence, n = 25(e) 95% confidence, n = 13(f) 95% confidence, n = 10

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Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

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probability and statistics
The distribution of study times for first year students follows a Normal distribution with standard deviation σ = 56 minutes. Suppose a sample of 325 students found that the mean study time for these students was x¯= 184 minutes per week. Use this to find a 96.05% confidence interval to estimate the mean study time for all students. We are 96.05% confident that the mean study time for first year students is between______minutes and _____ minutes What is the margin of error for your confidence interval?
A statistics practitioner took : random sample of 47 observations from a population whose standard deviation is 27 and computed the sample mean to be 99. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval = C. Estimate the population mean with 99% confidence. Confidence Interval =
How do I find the 90 percent confidence interval?
What is meant by the phrase "99% confidence interval" in this exercise? The phrase "99% confidence interval" means that if many intervals were constructed using the same methods and the same ▼ sample size, sample variance, population variance, sample mean, population mean, sample standard deviation, population standard deviation, then enter your response here% of those intervals would contain the true ▼ population variance. population standard deviation. sample variance. population mean. sample standard deviation. sample mean. sample size.
#40
You wish to develop a confidence interval for the population mean. The population standard deviation is known. We have a sample of 40 observations. We decide to use the 92% level of confidence. The appropriate value of z is: A.1.96 B.1.65 C.1.75 D.2.58
Working backwards, Part I: A 95% confidence interval for a population mean, μ, is given as (18.985, 21.015). This confidence interval is based on a simple random sample of 36 observations. Calculate the sample mean, the margin of error, and the sample standard deviation. Assume that all conditions necessary for inference are satisfied. Use the t-distribution in any calculations. Round your answers to 3 decimal places.Sample Mean: Margin of Error: Standard Deviation:
You intend to estimate a population mean with a confidence interval. You believe the population to have a normal distribution. Your sample size is 7.Find the critical value that corresponds to a confidence level of 99.9%.
A 95% confidence interval for a proportion is (0.62, 0.88). From this we can infer: The population proportion is 0.75 The population proportion is equal to the sample proportion O The population proportion is between 0.62 and 0.88 O The population proportion is likely to be between 0.62 and 0.88
Use technology to construct the confidence intervals for the population variance o? and the population standard deviation o. Assume the sample is taken from a normally distributed population. c= 0.99, s= 37, n 20 The confidence interval for the population variance is (Round to two decimal places as needed.) The confidence interval for the population standard deviation is (Round to two decimal places as needed.)
Ages of students: A simple random sample of 110 U.S. college students had a mean age of 23.05 years. Assume the population standard deviation is o =4.81 years. Construct a 90% confidence interval for the mean age of U.S. college students. Round the answers to two decimal places. A 90% confidence interval for the mean age of U.S. college students is 22.46 T< u <23.64

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