Confidence interval for the difference between population proportions. (Assume that the samples are randomly selected and independent.) Sample statistics: n₁ = 1000, x₁ = 250, and n₂ = 1200, X2 = 195; Construct a 98% confidence interval for the difference between population proportions p₁ – P2 (1.516, 3.021) (0.047, 0.128) (0.581, 1.819) (-0.621, 0.781)

Construct the confidence interval for the population mean μ.   c=0.98​, x=7.7​, σ=0.3​, and n= 47   A 98​% confidence interval for μ is ?

A random survey of 200 pregnant women in New York City conducted by Epstein andRogers indicated that 150 of them preferred a female obstetrician to a male obstetrician.a. Find a point estimate for p, the proportion of all pregnant women in New York Citywho prefer a female obstetrician.__________ b. Find a 99% confidence interval for the proportion p of all pregnant women living inNew York City who prefer a female obstetrician.

Confidence Interval for One Population Mean In 1903, a paper published by Abigail Camp Dimon, discussed the effect of environment on the shape and form of two sea snail species. Nassa obsoleta and Nassa trivittata. One of the variables that Dimon considered was the length of the shell. A random sample of 256 N. trivittata specimens was selected. The average shell length for the sample was 12 mm., with a standard deviation of 4 mm. Find the 95% confidence interval for the average shell length of all N. trivittata sea snails. What is the margin of error used to calculate this interval? Do not round.