The formation constant* of [[M(CN),]- is 5.30 x 1018, where M is a generic metal. A 0.140 mole quantity of M(NO3) is added to a liter of 0.780 M NaCN solution. What is the concentration of M+ ions at equilibrium? 1.74 x10-19 [M²+] = M Incorrect

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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.72PAE
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The formation constant* of [M(CN)2]¯ is 5.30 × 1018, where M is a generic metal.
A 0.140 mole quantity of M(NO3) is added to a liter of 0.780 M NaCN solution.
What is the concentration of M+ ions at equilibrium?
1.74 x10
[M²+] :
M
Incorrect
Transcribed Image Text:The formation constant* of [M(CN)2]¯ is 5.30 × 1018, where M is a generic metal. A 0.140 mole quantity of M(NO3) is added to a liter of 0.780 M NaCN solution. What is the concentration of M+ ions at equilibrium? 1.74 x10 [M²+] : M Incorrect
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