Question 19 of 25 The molar solubility of Mg(CN)2 is 1.4 x 10-5 M at a certain temperature. Determine the value of Ksp for Mg(CN). NEXT Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. Mg(CN)-(s) Mg (aq) 2 CN-(aq) Initial (M) Change (M) Equilibrium (M) O RESET 1.4 x 105 -1.4 x 10-5 2.8 x 10-5 -2.8 x 10-5 +x +2x -2x 1.4 x 10-5 +x 1.4 x 10- + 2x 1.4 x 10-5 - x 1.4 x 10- - 2x 2.8 x 10-5 + x 2.8 x 10+ 2r -X 28x 10-5 -x 2.8 x 10- 2x

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Determining the Solubility Product Constant (Ksp) for Mg(CN)₂**

The molar solubility of Mg(CN)₂ is given as 1.4 × 10⁻⁵ M at a certain temperature. Our objective is to determine the value of the solubility product constant (Ksp) for Mg(CN)₂.

**Guidance:**

Fill in the ICE (Initial, Change, Equilibrium) table to determine the concentrations of reactants and products in equilibrium based on the given solubility.

### ICE Table

|                      | Mg(CN)₂(s) | ⇌ | Mg²⁺(aq) | + | 2 CN⁻(aq) |
|----------------------|------------|---|----------|---|-----------|
| **Initial (M)**      |            |   |          |   |           |
| **Change (M)**       |            |   |          |   |           |
| **Equilibrium (M)**  |            |   |          |   |           |

### Choices for Values

Below the table, several options are available for each entry in the table:

- **Initial (M):** Usually starts at 0 for product ions as the solid begins to dissolve.
- **Change (M):** Indicated by typical chemical equilibrium terms such as ±x, 1.4 × 10⁻⁵, or 1.4 × 10⁻⁵ ± x.
- **Equilibrium (M):** Final concentrations are computed based on the changes that occurred.

Utilize these values to adequately fill the table and compute Ksp using the relation:

\[ K_{sp} = [\text{Mg}^{2+}][\text{CN}^-]^2 \]

This setup guides the calculations required to find the equilibrium concentrations and support the derivation of Ksp.
Transcribed Image Text:**Determining the Solubility Product Constant (Ksp) for Mg(CN)₂** The molar solubility of Mg(CN)₂ is given as 1.4 × 10⁻⁵ M at a certain temperature. Our objective is to determine the value of the solubility product constant (Ksp) for Mg(CN)₂. **Guidance:** Fill in the ICE (Initial, Change, Equilibrium) table to determine the concentrations of reactants and products in equilibrium based on the given solubility. ### ICE Table | | Mg(CN)₂(s) | ⇌ | Mg²⁺(aq) | + | 2 CN⁻(aq) | |----------------------|------------|---|----------|---|-----------| | **Initial (M)** | | | | | | | **Change (M)** | | | | | | | **Equilibrium (M)** | | | | | | ### Choices for Values Below the table, several options are available for each entry in the table: - **Initial (M):** Usually starts at 0 for product ions as the solid begins to dissolve. - **Change (M):** Indicated by typical chemical equilibrium terms such as ±x, 1.4 × 10⁻⁵, or 1.4 × 10⁻⁵ ± x. - **Equilibrium (M):** Final concentrations are computed based on the changes that occurred. Utilize these values to adequately fill the table and compute Ksp using the relation: \[ K_{sp} = [\text{Mg}^{2+}][\text{CN}^-]^2 \] This setup guides the calculations required to find the equilibrium concentrations and support the derivation of Ksp.
**Question 19 of 25**

The molar solubility of Mg(CN)₂ is \(1.4 \times 10^{-5}\) M at a certain temperature. Determine the value of Ksp for Mg(CN)₂.

**Instructions:**

Based on the setup of your ICE table, construct the expression for Ksp and then evaluate it. Do not combine or simplify terms.

\[ K_{sp} = \, \text{[          ]} = \, \text{[          ]} \]

**Available Options:**

- \([0]\)
- \([1.4 \times 10^{-5}]\)
- \([2.8 \times 10^{-5}]\)
- \([1.4 \times 10^{-5}]^2\)
- \([2.8 \times 10^{-5}]^2\)
- \([x]\)
- \([2x]^2\)
- \([1.4 \times 10^{-5} + x]\)
- \([1.4 \times 10^{-5} - x]\)
- \([1.4 \times 10^{-5} - 2x]\)
- \([1.4 \times 10^{-5} + x]^2\)
- \([2.8 \times 10^{-5} - x]\)
- \([2.8 \times 10^{-5} + 2x]\)

**Expression Options:**

- \(2.7 \times 10^{-15}\)
- \(1.1 \times 10^{-14}\)
- \(2.2 \times 10^{-14}\)
- \(3.9 \times 10^{-10}\)

**Reset Button:**

To start over, press the "RESET" button.
Transcribed Image Text:**Question 19 of 25** The molar solubility of Mg(CN)₂ is \(1.4 \times 10^{-5}\) M at a certain temperature. Determine the value of Ksp for Mg(CN)₂. **Instructions:** Based on the setup of your ICE table, construct the expression for Ksp and then evaluate it. Do not combine or simplify terms. \[ K_{sp} = \, \text{[ ]} = \, \text{[ ]} \] **Available Options:** - \([0]\) - \([1.4 \times 10^{-5}]\) - \([2.8 \times 10^{-5}]\) - \([1.4 \times 10^{-5}]^2\) - \([2.8 \times 10^{-5}]^2\) - \([x]\) - \([2x]^2\) - \([1.4 \times 10^{-5} + x]\) - \([1.4 \times 10^{-5} - x]\) - \([1.4 \times 10^{-5} - 2x]\) - \([1.4 \times 10^{-5} + x]^2\) - \([2.8 \times 10^{-5} - x]\) - \([2.8 \times 10^{-5} + 2x]\) **Expression Options:** - \(2.7 \times 10^{-15}\) - \(1.1 \times 10^{-14}\) - \(2.2 \times 10^{-14}\) - \(3.9 \times 10^{-10}\) **Reset Button:** To start over, press the "RESET" button.
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