A force vector has a magnitude of 592 newtons and points at an angle of 45° below the positive x axis. What are (a) the x scalar component and (b) the y scalar component of the vector? (a) Fx Number 419 Units N (b) Fy= Number i 419 Units N

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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this is a practice problem. Would this answer not be 592(sin)45?

A force vector has a magnitude of 592 newtons and points at an angle of 45° below the positive x axis. What are (a) the x scalar
component and (b) the y scalar component of the vector?
(a) F
Number 419
Units N
(b) Fy
Number i 419
Units N
Transcribed Image Text:A force vector has a magnitude of 592 newtons and points at an angle of 45° below the positive x axis. What are (a) the x scalar component and (b) the y scalar component of the vector? (a) F Number 419 Units N (b) Fy Number i 419 Units N
Expert Solution
Step 1: Determine the given variables:

The magnitude of the force vector is F equals 592 text  N end text

The angle of the force F below the +x axis is theta equals 45 degree

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