The force experienced by a particle of charge q moving with a velocity v in a uniform magnetic field Bisgiven by Fq (v x B) then:O a. Fis always perpendicular to q and BO b.q is always parallel to v and BO . Fis always perpendicular to v and BO d.vis always perpendicular to Fand B

Direction of cross product is given by Fleming's left hand rule

Answered: The force experienced by a particle of…

The force experienced by a particle of charge q moving with a velocity v in a uniform magnetic field Bis given by Fq(v x B) then

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

An electron that is accelerated from rest through a potential of 4.00 kV enters the velocity filter, consisting of a parallel plate capacitor and a magnetic field. The E-field between the parallel capacitor plates is 7.80 x 106 N/C. What magnetic field (in T) is required so that the electrons are not deflected? The mass of an electron is 9.11 x 10-31 kg. (Ignore relativistic effects for high velocities.)
The velocity vector of a particle of positive charge is = (2î – 4ĵ + 1k) m/s. The particle propagates through a region in which the magnetic field vector is given by B = (1î + 2ĵ – 3k) T. Determine the magnitude and direction of the force experienced by the particle.
It carries a uniformly distributed total charge q on a circular ring of radius R. The ring rotates with constant angular velocity ω about an axis passing through its center and perpendicular to its surface.On the axis of the circle and at a distance of z=R/2 from the circleWhat is the magnetic field at the point?
The top and bottom faces of a rigid insulating box of dimensions axbxh and mass m are charged with uniform surface charge densities and - respectively and the box is placed in a uniform horizontal magnetic field B = Bj. Assuming free space conditions and h negligibly small as compared to the dimensions a and b, find how much velocity will the box acquire after the magnetic field is switched off? b (a) σabhB. 20abhBo haß (b) Ĵ 2² дам Ø = hab m m σabhBoi 20abhBoi ^ SEM = 11/11/201 SE₁.de + (d) = m m банквой m (c) ZA Eup Edou
A particle of charge +q and mass m moves with velocity v → 0 pointed in the +y-direction as it crosses the x-axis at x = R at a particular time. There is a negative charge –Q fixed at the origin, and there exists a uniform magnetic field B → 0 pointed in the +z-direction. It is found that the particle describes a circle of radius R about –Q. Find B → 0 in terms of the given quantities.
Two long, straight current-carrying wires cross each other at an angle shown below. Assuming that the wires are electrically insulated from each other, determine the strength and direction of the magnetic field at point P
A long, straight wire lies on a horizontal table in thexy - plane and carries a current of 1.20 µA in the positivex - direction along the x - axis. A proton is traveling in the negativex - direction at speed 2.30 x 104 m/s a distance d abovethe wire (i.e., z = d ). (a) What is the direction of the magneticfield of the wire at the position of the proton? (b) Whatis the direction of the magnetic force acting on the proton?(c) Explain why the direction of the proton’s motion doesn’tchange. (d) Using Newton’s second law, find a symbolicexpression for d in terms of the acceleration of gravity g, theproton mass m, its speed v, charge q, and the current I.(e) Find the numeric answer for the distance d using theresults of part (d).
A particle with charge q = 1.1 C and a long wire carrying current I = 5 A is on the ry-plane at the moment the charge is at point P at distance L. d = 0.5 cm from the wire and has d velocity v = 1.9 m/s in the - direction. What is the magnitude of the magnetic force acting on the charge in units of nanonewtons? (Рo — 4т х 10 7т-m/A) Answer:
A long straight wire of a radius of 10.0 cm carries a steady current 34 A that is uniformly distributed through the cross-section of the wire. Calculate the magnetic field ( in units of uT) at a distance of 7.5 cm from the center of the wire?
A particle of mass m, charge q and position x moves in a constant, uniform magnetic field B which points in a horizontal direction. The particle is also under the influence of gravity, g , acting vertically downwards. Write down the equation of motion and show that it is invariant under translations x -> x + x0. Obtain x = \alpha x \times n + gt + a where \alpha = qB/m, n is a unit vector in the direction of B and a is a constant vector. Show that, with a suitable choice of origin, a can be written in the form a = an. By choosing suitable axes, show that the particle undergoes a helical motion with a constant horizontal drift. Suppose that you now wish to eliminate the drift by imposing a uniform electric field E. Determine the direction and magnitude of E. Training
A long straight wire of a radius of 10.0 cm carries a steady current 40.7 A that is uniformly distributed through the cross-section of the wire. Calculate the magnetic field ( in units of uT) at a distance of 7.5 cm from the center of the wire?
A long, straight wire lies on a horizontal table in the xy -plane and carries a current of 1.20 μA in the positive x -direction along the x-axis. A proton is traveling in the negative x -direction at speed 2.30 × 104 m/s a distance d above the wire (i.e., z = d). (a) What is the direction of the magnetic field of the wire at the position of the proton? (b) What is the direction of the magnetic force acting on the proton? (c) Explain why the direction of the proton’s motion doesn’t change. (d) Using Newton’s second law, find a symbolic expression for d in terms of the acceleration of gravity g, the proton mass m , its speed v, charge q, and the current I (e) Find the numeric answer for the distance d using the results of part (d).