The following kinetic data were collected for prostaglandin endoperoxide synthase, an enzyme involved in pain and inflammation. Using data in the first two columns, use a graphical analysis to determine the Vmax and the Km of the enzyme.Ibuprofen (Advil) is an inhibitor of prostaglandin endoperoxide synthase. By inhibiting this enzyme, ibuprofen helps to reduce pain and fever. Using the data in the first and third columns, determine the type of inhibition that ibuprofen exerts on prostaglandin endoperoxide synthase. In the presence of the inhibitor, determine the Vmax and the Km of the enzyme.| [S] mM | Product formed mmol/min | Product formed (mmol/min) with 10 mg/mL ibuprofen ||--------|--------------------------|-----------------------------------------------------|| 0.5 | 23.5 | 16.67 || 1.0 | 32.2 | 25.25 || 1.5 | 36.9 | 30.49 || 2.5 | 41.8 | 37.04 || 3.5 | 44.0 | 38.91 |In this experiment, substrate concentration [S] is measured in mM (millimolar) and product formation rate is measured in mmol/min (millimoles per minute). The data includes rates without and with the presence of ibuprofen at a concentration of 10 mg/mL, indicating its inhibitory effects on the enzyme. The table allows comparison between these two conditions for analysis of enzyme kinetics.

In order to solve this question, first, we need to draw the Lineweaver-Burk plot (LB plot) and find…

Answered: The following kinetic data were…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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One of your colleagues has obtained a sample of muscle phosphorylase b that is known to be relatively inactive. She has approached you for advice on how to set up an appropriate assay. She has the following items available, not all of which are appropriate for this study. Help her out by selecting the items that she should use and what their purpose is in the assay, and then explain why each of the other items would not be useful. 1. 100 UM AMP 2. 100 UM GTP 3.100 uM glucose 4. 100 uM glucose 6-phosphate 5. Branched glycogen 6. Amylose (i.e. unbranched glycogen) 7.50 mM HEPES buffer, pH 7.5 8. 50 mM potassium phosphate buffer, pH 7.5 Write out a short explanation for each of the above items, and upload your answers by the due date.
Many enzymes obey simple Michaelis–Mentenkinetics, which are summarized by the equationrate = Vmax [S]/([S] + Km)where Vmax = maximum velocity, [S] = concentration ofsubstrate, and Km = the Michaelis constant.It is instructive to plug a few values of [S] into theequation to see how rate is affected. What are the rates for[S] equal to zero, equal to Km, and equal to infinite concen-tration?
Use the relationships revealed by a Lineweaver–Burk plot and the table of enzyme performance to calculate the ?max and ?M of the enzyme with no inhibitor, with inhibitor A, and with inhibitor B. Substrate concentration, [S], has units of micromolar, μM. Enzyme velocity, ?0, has units of micromole per minute, (μmol/min). Using data from only the extremes of the [S] range is unreliable. Select the type of inhibition displayed by inhibitor A. competitive noncompetitive uncompetitive Select the type of inhibition displayed by inhibitor B. competitive noncompetitive uncompetitive
In an enzyme experiment, when the enzyme is added only to the substrate, the Vmax value is 0.828 and the Km value is 17.76. When the substrate and activator are added to this enzyme, the Vmax is 0.964 and the Km value is 10.6066. When substrate and inhibitor are added to the enzyme, the Vmax value is 0.550 and the Km value is 11.34. Estimate the effect of the substance added. Are these substances suitable activators/inhibitors for the laccase enzyme?
Using equilibrium argument, why does Km apparently increase, decrease or stay the same in uncompetitive inhibition?
Neutral sphingomyelinase 2 converts sphingomyelin into ceramide and phosphorcholine. What kind of enzyme is it? Assume Vmax is 35 µM min-1. When you provide 3.0 x 10-5 M of sphingomyelin, you observe an initial velocity of 6.0 µM min-1. Calculate the KM.
Based on the Lineweaver-Burke plot attached. Kinetic data were generated in the (1) absence of any inhibitor, (2) presence of 15 µM of a reversible inhibitor, or (3) presence of 20 µM of a second (distinct) reversible inhibitor. Purified enzyme concentration was 5 µM. The y-intercept of Lines (A) and (B) is 0.9 sec/uM; the y-intercept of Line (C) is 0.3 sec/uM. The slope of Line (A) is 1.8 sec; the slope of Lines (B) and (C) is 0.6 sec. Calculate the Vmax of the reaction represented by Line (C). Show all mathematical work, please.
Table 1 shows the kinetic data that have been obtained for glucoamylase from Aspergillus niger at different temperatures in the production of glucose from maltodextrin. The rates of reaction measured are using an enzymes concentration of 0.003 μmolml-1. Outline and describe the reaction scheme of the production of glucose from maltodextrin by using glucoamylase.
An experiment was carried out to measure the reaction rate of hydrolysis of acetylcholme (substrate) with serum enzymes (Eadie, 1949). In the experiment, two experiments were conducted, namely experiment 1 without using a prostigmine inhibitor and experiment 2 using a prostigmine inhibitor at 1.5 x 10^-7 mol/l. the data obtained are: a. Is prostigmine competitive or noncompetitive inhibitor? b. determine the value of km and rmax for the two experiments, compare
The table below lists experimental conditions that can be applied to a reaction catalyzed by a hypothetical Michaelis–Menten enzyme. For each experimental condition described, complete the table to indicate as precisely as possible the effect (no change, half as large doubles, increases, decreases) on the maximal velocity, Vmax, and Michaelis constant, KM, of the hypothetical enzyme.
when the substrate concentration of certain enzyme is quarter than Michaelis constant, the velocity of enzyme will be... * 3/4 V max 1/5 V max Non of these 2/5 V max 1/4 V max 3/5 V max
A newly developed drug is suspected to act by inhibiting its enzymatic target. To test this, the rates of reaction in the presence and absence of the new drug were determined. The results of these experiments have been plotted as a double reciprocal plot shown in figure 1 below. Using this figure, calculate the values of Vmax and Km for the enzyme in the presence and absence of the drug. Based on the figure and your answer, what type of inhibition is the new drug displaying? Briefly explain how this type of inhibition exerts its action on an enzyme.

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