The following grammar is an indirect left recursive grammarS→ Bb aB→ SalbStrings of the language generated by this grammar are of the followingform:L= {a(w)m, bb(w)" | w =, m, n EN }This indirect left recursive grammar can be transformed to a right recursivegrammar as follows:ST→This right recursive grammar is an LL() grammar.

Detailed answer show blownExplanation:. This can cause problems for parsers, as they can get stuck…

Answered: The following grammar is an indirect…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Predictive parsers are recursive descent parsers that need no backtracking and can be constructed for a class of grammars called LL (1). The first "L" in LL (1) indicates that, scanning the input from left to right. The second "L" in LL (1) signifies that, producing a leftmost derivation. The "1" in LL (1) indicates that, using one input symbol of lookahead at each step to make parsing action decisions. Like recursive descent, the LL (1) technique is top-down, goal oriented, and predictive. Consider the grammar G5: S → iEtSS′|a S′ → eS|ԑ E → bConstruct the LL (1) parsing table for the grammar G5 and use the LL (1)parsing table for the grammar G5 to check whether the grammar G5 is LL (1). Algorithm sheet: Algorithm for Constructing LL (1) Parsing Table Input: Grammar G.Output: Parsing table M.Method: For each production A → a of the grammar, do the following: Step 1: For each terminal "a" in ????? (a), add A → a to M[A, a].Step 2: If ? is in ????? (a), then for each terminal b in…
Given the following CFG A → A+B A+ A-B A R R⇒ R/B R→ R*B Rarit B-> (A)|r|t a. Eliminate left recursion and backtracking and write the new grammar.. b. Write the FIRST and FOLLOW sets for A, B, and R.,
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Remove lambda rules from the following grammar. Your answer must include the NULL set.S → aS | bS | BB→ bb | C | λ C →cC | λ
For LL(1) parsers, the following must happen: Chose the correct anwser below: Grammar can have left recursion but not ambiguous Grammar can be ambiguous but no left recursion Grammar can be ambiguous and have left recursion as well. Grammar must be free of left recursion and not ambiguous
Let G = (V, E, R, S) be a grammar with V= {S, H, Gm J}; = {h, g. j}; and the set of rules: H>h | hJG G> Gg | Sg | HgJ J→ jH | HHJ| Jj Convert this grammar to a PDA using the method we described.
Consider the grammar exp->atom | listatom->num | idlist-> ( seq )seq-> seq exp | expa. Remove the left recursionb. Construct First and Follow sets for the nonterminals of the resulting grammar
Consider the following grammar G: The grammar is not suitable for a top-down predictive parser. Identify the problem and correct it by rewriting the grammar as an LL(1) grammar for the same language
The language generated by the following grammar is S→ SaaS | C This grammar is left recursive, hence, it is not LL(k) for any k. Fill out the blank below to make the resulting grammar equivalent to the above grammar but with no left recursion. Is the resulting grammar LL(k)? Yes If your answer is YES, then what is the value of k? k = No

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