The following function will correctly return true if its argument is an odd integer bool Isodd (int x) { return (x / 2 == 1); } True False

In C programming, if the return type of a function is Void how can you implement assert statements?  For example, Void ceasar(int n, char*x); //if char = c and n = 3 output == f  how do i use assert statements as this does not work assert (caesar(3,c)==f);

Here is a function that is supposed to return True if word (any string) ends with "s" and False otherwise: def ends_with_s(word):if len(word) < 1:return False    return word[-1] == "s" Here is the test function I am using to test ends_with_s: def test_ends_with_s():    assert(ends_with_s("cats")) # option 1    assert(ends_with_s("") is False) # option 2    assert(ends_with_s("apple") is False) # option 3    assert(ends_with_s("S")) # option 4   Rewrite ends_with_s so that the test passes

*Modify the program so that the user will error trap for only 1 and 0 as an input.   *If the user enters an input other than 1 or 0 display an error message and request the user enter that input again.  *Do this for all inputs in the code.     # User defined function for logic OR# The function takes two parameters and returns a single intdef OR(a: int, b: int)->int:# If a is equal to 1 return 1if a == 1 :return 1# If b is equal to 1 return 1elif b == 1 :return 1# If a and b is equal to 0 return 0else :return 0 # User defined function for logic NOR# The function takes two parameters and returns a single intdef NOR(a: int, b: int)->int:# If a is equal to 0 and b is also equal to 0 return 1if a == 0 and b == 0 :return 1# If a is equal to 0 and b is equal to 1 return 0elif a == 0 and b == 1 :return 0# If a is equal to 1 and b is also equal to 0 return 0elif a == 1 and b == 0 :return 0# If a is equal to 1 and b is also equal to 1 return 0elif a == 1 and b == 1 :return 0 # User defined…

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