Given a boolean expression consisting of the symbols 0 (false), 1 (true), & (AND), I (OR), and / (XOR), and a desired boolean result value result, create a function that counts the number of ways the expression may be parenthesized such that it evaluates to result. The expression should be completely parenthesized (for example, (0) A(1)) but not excessively (for example, (((0)) / (1))). EXAMPLE \scount Eval("l/01011", false) yields 2 counts. "0&0&0&1All0", true) = 10

When the robot makes a turn, it would be useful to have an operation to perform on d to represent this turn. This is because after making a turn, the new value of d will depend on the old value of d. Complete the table for the new values of d if the robot is turning left or right.Then determine an expression in terms of d that will give the new position if the robot turns left and another expression if the robot turns right. Type these expressions in the last row of the table. Attached is the table I completed. All rows are correct except the last one. I'm not sure what my error is.

please code in python Find the Error The following function takes in a positive integer and returns True if the integer is divisible by at least one integer between 2 and 7, inclusive, or False otherwise.  Or at least, that’s what it’s supposed to do; there is a logic error that causes it to fail (for example, it should return True when passed in 15, but it returns False instead).  Find the error and fix it.  If you’re working in a pair, make sure that both of you are able to explain the error to your TA.    Hints: As with most logic errors, the first thing you should do is put in print statements. Print out what i is at each step of the loop. At what point can you safely return False (that is, how many values of i do you have to check before you can be sure num isn't divisible by any of them)?   def div27(num):     for i in range(2,8):         if num % i == 0:             return True         else:             return False

2. Express the following Boolean expressions in simpler form; that is, use fewer operators. x is an int (b) x < 2 || x == 2