The following function f uses recursion: def f(n): if n <= 1 return n else return f(n-1) + f(n-2) 5 Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but without recursion? a) def f(n): a <- 0 b <- 1 if n = 0 return a elsif n = 1 return b else for i in 1..n c <- a + b a <- b b <- c return b f(n): a <- 0 i <- n while i > 0 a <- a + i + (i-1) return a f(n): arr[0] <- 0 arr[1] <- 1 if n <= 1 return arr[n] else for i in 2..n arr[i] <- arr[i-1] + arr[i-2] return arr[n] f(n): arr[0..n] <- [0, ..., n] if n <= 1 return arr[n] else a <- 0 for i in 0..n a <- a + arr[i] return a

The following function f uses recursion: def f(n): if n <= 1 return n else return f(n-1) + f(n-2) 5 Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but without recursion? a) def f(n): a <- 0 b <- 1 if n = 0 return a elsif n = 1 return b else for i in 1..n c <- a + b a <- b b <- c return b f(n): a <- 0 i <- n while i > 0 a <- a + i + (i-1) return a f(n): arr[0] <- 0 arr[1] <- 1 if n <= 1 return arr[n] else for i in 2..n arr[i] <- arr[i-1] + arr[i-2] return arr[n] f(n): arr[0..n] <- [0, ..., n] if n <= 1 return arr[n] else a <- 0 for i in 0..n a <- a + arr[i] return a

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter15: Recursion

Section: Chapter Questions

Problem 6PE

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The following function f uses recursion:def f(n):if n <= 1return nelse return f(n-1) + f(n-2)Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but without recursion?a) def f(n):a <- 0b <- 1 if n = 0return aelsif n = 1 return belsefor i in 1..nc <- a + b a <- b b <- c return bb) def f(n):a <- 0i <- n while i > 0 a <- a + i + (i-1) return ac) def f(n): arr[0] <- 0 arr[1] <- 1 if n <= 1return arr[n]elsefor i in 2..n arr[i] <- arr[i-1] + arr[i-2]return arr[n]d) def f(n): arr[0..n] <- [0, ..., n] if n <= 1return arr[n]elsea <- 0 for i in 0..n a <- a + arr[i]return a
The following function f uses recursion:def f(n):if n <= 1return nelsereturn f(n-1) + f(n-2)5Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but without recursion? a) def f(n):a <- 0b <- 1if n = 0return aelsif n = 1return belsefor i in 1..nc <- a + ba <- bb <- creturn b b) def f(n):a <- 0i <- nwhile i > 0a <- a + i + (i-1)return a c) def f(n):arr[0] <- 0arr[1] <- 1if n <= 1return arr[n]elsefor i in 2..narr[i] <- arr[i-1] + arr[i-2]return arr[n] d) def f(n):arr[0..n] <- [0, ..., n]if n <= 1return arr[n]elsea <- 0for i in 0..na <- a + arr[i]return a
The following function f uses recursion:def f(n):if n <= 1return nelsereturn f(n-1) + f(n-2)Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but withoutrecursion?a) def f(n):a <- 0b <- 1if n = 0return aelsif n = 1return belsefor i in 1..nc <- a + ba <- bb <- creturn bb) def f(n):a <- 0i <- nwhile i > 0a <- a + i + (i-1)return ac) def f(n):arr[0] <- 0arr[1] <- 1if n <= 1return arr[n]elsefor i in 2..narr[i] <- arr[i-1] + arr[i-2]return arr[n]d) def f(n):arr[0..n] <- [0, ..., n]if n <= 1return arr[n]elsea <- 0for i in 0..na <- a + arr[i]return a
The following function f uses recursion: def f(n): if n <= 1 return n else return f(n-1) + f(n-2) Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but without recursion? a) def f(n): a <- 0 ъ <-1 if n = 0 return a elsif n = 1 return b else for i in 1..n C <- a + b a <- b b <- c return b
CodeW X bFor fun X C Solved x b Answer + x https://codeworko... CodeWorkout X265: Recursion Programmlng Exercise: GCD The greatest common divisor (GCD) for a pair of numbers is the largest positive integer that divides both numbers without remainder. For function GCD , write the missing base case condition and action. This function will compute the greatest common divisor of x and y.You can assume that x and y are both positive integers and that x > y. Greatest common divisor is computed as follows: = x and GCD(x, y) = GCD(y, x % y). Examples: GCD (6, 4) -> 2 Your An swer: 1 public int GCD(int x, int y) { if > { 2. > 3. } else { 4. return GCD(y, x % y); 9. { 7. 1:09 AM 50°F Clear 1V 1. 12/4/2021 甲

Write the definition of a recursive function int simpleSqrt(int n) The function returns the integer square root of n, meaning the biggest integer whose square is less than or equal to n. You may assume that the function is always called with a nonnegative value for n. Use the following algorithm: If n is 0 then return 0. Otherwise, call the function recursively with n-1 as the argument to get a number t. Check whether or not t+1 squared is strictly greater than n. Based on that test, return the correct result. For example, a call to simpleSqrt(8) would recursively call simpleSqrt(7) and get back 2 as the answer. Then we would square (2+1) = 3 to get 9. Since 9 is bigger than 8, we know that 3 is too big, so return 2 in this case. On the other hand a call to simpleSqrt(9) would recursively call simpleSqrt(8) and get back 2 as the answer. Again we would square (2+1) = 3 to get back 9. So 3 is the correct return value in this case.
The following function f uses recursion: def f(n): if n <= 1 return n else return f(n-1) + f(n-2) Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but without recursion? a) def f(n): a <- 0 b <- 1 if n = 0 return a elsif n = 1 return b else for i in 1..n c <- a + b a <- b b <- c return b b) def f(n): a <- 0 i <- n while i > 0 a <- a + i + (i-1) return a c) def f(n): arr[0] <- 0 arr[1] <- 1 if n <= 1 return arr[n] else for i in 2..n arr[i] <- arr[i-1] + arr[i-2] return arr[n] d) def f(n): arr[0..n] <- [0, ..., n] if n <= 1 return arr[n] else a <- 0 for i in 0..n a <- a + arr[i] return a
CodeW For fun X C Solved https://codeworkou... 臺亂 CodeWorkout X272: Recursion Programming Exercise: Is Reverse For function isReverse, write the two missing base case conditions. Given two strings, this function returns true if the two strings are identical, but are in reverse order. Otherwise it returns false. For example, if the inputs are "tac" and "cat", then the function should return true. Examples: isReverse("tac", "cat") -> true Your Answer: 1 public boolean isReverse(String s1, String s2) { 2. if > 3. 4. else if > return true; return false; 5. 6. else { String s1first = String s2last return s1first.equals (s2last) && 51. substring(0, 1); s2, substring(s2.length() 1); 7. 8. 6. isReverse(s1.substring(1), s2.substring(0, s2.length() 1)); { 12} 1:11AM 50°F Clear 12/4/2021
CodeW X b For func x C Solved X b Answer X https://codeworkou... CodeWorkout X270: Recursion Programming Exercise: Count Characters For function countChr() write the missing part of the recursive call. This function should return the number of times that the letter "A" appears in string "str". Recall that str.substring(a) will return the substring of str from position a to the end of str, while str.substring (a, b) will return the substring of str starting at position a and continuing to (but not including) the character at position b. Examples: countChr ("ctcoWCAt") -> 1 Your AnsSwer: 1 public int countChr(String str) { 2. if (str.length() return 0; } (0 4. { int count = 0; www. 5. 9. if (str.substring(0, 1).equals("A")) { count = 1 7. { 9. return count + > 1:10 AM 50°F Clear 12/4/2021 呼
By using a recursive function to find s value: S= 2/x – 4/x + 6/x – 8/x .. 2n/x
2. Consider the following function: def func1(n): output = 1 for i in range (1, n) : output = i return output Rewrite the function as a recursive function.
Which is the base case of the following recursion function: def mult3(n): if n == 1: return 3 else: return mult3(n-1) + 3 else n == 1 mult3(n) return mult3(n-1) + 3