The following function f uses recursion: def f(n): if n <= 1 return n else return f(n-1) + f(n-2) Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but without recursion? a) def f(n): a <- 0b <- 1 if n = 0 return a elsif n = 1 return b else for i in 1..n c <- a + b a <- b b <- c return b b) def f(n): a <- 0i <- n while i > 0 a <- a + i + (i-1) return a c) def f(n): arr[0] <- 0 arr[1] <- 1 if n <= 1 return arr[n] else for i in 2..n arr[i] <- arr[i-1] + arr[i-2] return arr[n] d) def f(n): arr[0..n] <- [0, ..., n] if n <= 1 return arr[n] else a <- 0 for i in 0..n a <- a + arr[i] return a
The following function f uses recursion: def f(n): if n <= 1 return n else return f(n-1) + f(n-2) Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but without recursion? a) def f(n): a <- 0b <- 1 if n = 0 return a elsif n = 1 return b else for i in 1..n c <- a + b a <- b b <- c return b b) def f(n): a <- 0i <- n while i > 0 a <- a + i + (i-1) return a c) def f(n): arr[0] <- 0 arr[1] <- 1 if n <= 1 return arr[n] else for i in 2..n arr[i] <- arr[i-1] + arr[i-2] return arr[n] d) def f(n): arr[0..n] <- [0, ..., n] if n <= 1 return arr[n] else a <- 0 for i in 0..n a <- a + arr[i] return a
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
The following function f uses recursion:
def f(n):
if n <= 1
return n
else return f(n-1) + f(n-2)
Let n be a valid input, i.e., a natural number. Which of the following functions returns the same result but without recursion?
a) def f(n):
a <- 0b <- 1 if n = 0
return a
elsif n = 1 return b
else
for i in 1..n
c <- a + b a <- b b <- c return b
b) def f(n):
a <- 0i <- n while i > 0 a <- a + i + (i-1) return a
c) def f(n): arr[0] <- 0 arr[1] <- 1 if n <= 1
return arr[n]
else
for i in 2..n arr[i] <- arr[i-1] + arr[i-2]
return arr[n]
d) def f(n): arr[0..n] <- [0, ..., n] if n <= 1
return arr[n]
else
a <- 0 for i in 0..n a <- a + arr[i]
return a
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