The following figure represents a 3-nodes, two-element truss structure with identical cross-sectional area A = 100 mm2 and modulus E = 200 GPa for each element. It is supported by a pin at global node 1, an inclined roller at 135˚ at global node 2 and a horizontal roller at global node 3. A force P = 400 kN is applied at global node 2. Using the direct approach and the minimum number of linear finite elements, what would be the displacement at the global node 2 of the inclined roller in its local coordinate system?

PE Problem for Module 2.1: Solve the complex truss below by the method of substitution. See component reactions at the supports. Match the axial bar force by ticking the circle that corresponds to your answer according to your solution. * 2m 16KN 4m 16 KN a 1m 4m 4m 10 KN 10 KN

Q1 (а) A hollow circular post ABC as shown in Figure Q1 (a) supports a load P, = 65B5 N acting at the top. P2 is applied around the cap plate at B. The outer diameters and thicknesses of the upper and lower parts of the post are dAB = 30 mm, tu =1A mm, dzc = 50 mm, and t3c =9 mm , respectively. A=1 B=0 (i) Calculate the normal stress o AR on the upper part of the post. (ii) If it is desired that the lower part of the post have the same compressive stress as the upper part, what should be the magnitude of the load P,? (111) If Pi remains at 65B5 N and P2 is now set at 10050 N, what is the new thickness of BC that will result in the same compressive stress in both parts?

please help solve and explain