The following DNA sequence is a bacterial promoter with numbered nucleotides. The 3' end is the transcriptional start site. 5 1 2 3 4 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 T A с G T CA T T GCCA ATT CT CT 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 ATG CATCTTATA A TTATGG C 41 42 43 44 45 TCGG T-3' Which nucleotide number is the 5' end of -35 site: Which nucleotide number is the 3' end of -35 site: Which nucleotide number is the 5' end of -10 site: Which nucleotide number is the 3' end of -10 site: 30 57 na
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- CTA GCC CTC CGT TAC TAG TTA CCT ACT TAT TCA ATT TTG TAA ACG CTC ATC CGA ACC CGC TTT TAA TTG CCC ACT TAG TCG ATT ACC CGT TTA TGT TAA TTA CCT ATC 1. Build the mRNA molecule matching the RNA nucleotides to the DNA nucleotides properly letter by letter. (assume that the mRNA is bacterial there are not intros to cut out) 2. Figure out the tRNA triplet (codons) that would fit the mRNA triplets. (letter by letter) 3. Look up for each tRNA codon and find the corresponding symbol and amino acid abbreviations. The symbols should spell out a meaningful English message.CTA GCC CTC CGT TAC TAG TTA CCT ACT TAT TCA ATT TTG TAA ACG CTC ATC CGA ACC CGC TTT TAA TTG CCC ACT TAG TCG ATT ACC CGT TTA TGT TAA TTA CCT ATC 1. Build the mRNA molecule matching the RNA nucleotides to the DNA nucleotides properly letter by letter. (assume that the mRNA is bacterial there are not intros to cut out)Figure 1 is a bacterial gene (1-180). The first base to be transcribed is the base located at position 77. 45 5' TTGGT CTTGG TCGGA TTCCA GAGGA TGAAG TGTTG ACAGC GCATT 3' 3 AACCA GAACC AGCCT AAGGT CTCCT ACTTC ACAAC TGTCG CGTAA 5' 46 5 AATTG ACCTT GCTGT ATTAT AGCCA AGGAC AGATC TACGA GCATG 3' 3 TTAAC TGGAA CGACA TAATA TCGGT TCCTG TCTAG ATGCT CGTAC 5' 91 5 TGCGA ACCGC AAGCA TTCGT TCTCC TAGGC TACTC GATCC CGTAA 3' 3 ACGCT TGGCG TTCGT AACCA AGAGG ATCCG ATGAG CTAGG GCATT 5 77 90 110 135 136 5 TGATG TAGCT GATTC TGTTG AAAGG CTCCT TTTGG AGCCT TTTTT 3 3' ACTAC ATCGA CTAAG ACAAC TTTCC GAGGA AAACC TCGGA AAAAA 5 156 180 Figure 1. Illustrate how termination of transcription occurs in the gene above. (Hint: position from 156 to 180)
- V S X It F3 3 9999999 E D G Which letter indicates the amino end of the growing polypeptide? с F4 $ 4 A Q Search R F mRNA F5 er ge % UAC 5 V T F6 GGG AUGCCCACG G 6 B Y De F7 H ►/11 v lo & 7 7 F8 U 4 N UAG * 8 865 F9 8 1 5 G Мо Alt F10 ( 9 9 K 2 O < " ) 6 0 F11 1 P* L 3 • V A 30 F12 ; { I Ctrl = 332 PM 4/7/2023 ? + 1 } 1 11 A 1 G Backspace Home Delete Enter Shift PgUp PgDnWhich process is illustrated in the diagram? Pre-mRNA ron Lariat BI F4 Exon 1 O Replication R C F Step 1 Transcription Step 2 Intron Q Search 5 T mRNA Eon 1 Exon 2 G Exon 2 F6 Elon Y F7 H & 7 U F8 *00 * 8 99+ J₁ 85 F9 ALTER 9 B 5 O V BN MO Alt F10 K 2 F11 0 L P < F12 10:01 AM 4/8/2023 Ctrl 10The following segment of DNA is part of the RNA-coding sequence of a transcription unit. If the bottom strand is template, which of the following RNA sequences would be transcribed? DNA: 5-'ATAGGCGATGCCA-3' 3'-TATCCGCTACGGT-5' O 5'-UAUCCGCUACGGU-3' O 5'-ACCGUAGCGGAUA-3' O 5'-AUAGGCGAUGCCA-3' O 5'-UGGCAUCGCCUAU-3'
- thank you#4 3 E D The arrow in the diagram below indicates the direction of transcription. B C A HE ATGCCGCA TACGGCOTTAGAR, CLI A O OB AUGCCGCAAUCUGUUCAC Which letter indicates an RNA strand? R Q Search F F5 % 5 V FTCACOCACTO T F6 G F Direction of synthesis < 6 FISC B Y F7 TCATOTO H & 7 PTGAGTACAS F8 U 99+ *00 8 J D с TACCACGTA ATGGTGCAT F9 LCAMI TITTE ( N M 124 SD 9 K MO Alt F P F12 10:04 AM 4/8/2023 10 CA binding site for RNA polymerase is called a ________. a. gene c. codon b. promoter d. protein
- The following gene sequence of nucleotides is found on the template (non-coding) strand of a molecule of DNA from a bacterial cell. The promoter of the gene is highlighted in bold letters and the +1 is underlined. Use the genetic code at the end of this packet to answer the following questions. 3'-AGGCATATTACGATGCCGGTACTTGATGATGACGGACCCATTATAGGACATATG-5' a) What is the sequence of the mRNA strand that will be transcribed from this piece of DNA? Indicate which is the 5’ and which is the 3’ end of the mRNA. b) What is the amino acid sequence that will be translated from this piece of DNAw/opCulGACU GAC UC 4C According to the Genetic Code Sheet below, which of the following amino acid sequences corresponds to this MRNA strand? CỤC AAG UGC UUC PHE GLU ASP SER ALA TYR U A STOP A GU VAL U CIS U U G A STOP IG TRP ARG AC U LEU SER UG PRO ASN HIS THE GLN MET ILE ARG O a lys-leu-cys-phe O b glu-cys-pro-phe leu-lys-cys-phe O d leu-glu-leu-val U...pdfE D ot OH ON O Replication R SORO Transcription ORNA processing Translation Gene expression 657 F Q Search % T G LOCLE Y F7 & 87 F8 U 99+ 8 F9 53879 10 F10 O 2 H J K L CV BN MO < F12