The five-bolt connection shown must support an applied load of P = 400 N. The thickness of the axial member: = 1 mm. and the width = 16 mm If the ultimate shear stress in the bolts must be limited to 250 MPa with F.O.S = 2.5 . And the ultimate normal stress in the axial member = 180 MPa, with F.O.S = 2.9 , And the ultimate bearing stress in the axial member = 95 MPa, F.O.S = 1.3 Determine the minimum bolt diameter that may be used in the connection? In correct way

The five-bolt connection shown must support an applied load of P = 400 N. The thickness of the axial member: = 1 mm. and the width = 16 mm If the ultimate shear stress in the bolts must be limited to 250 MPa with F.O.S = 2.5 . And the ultimate normal stress in the axial member = 180 MPa, with F.O.S = 2.9 , And the ultimate bearing stress in the axial member = 95 MPa, F.O.S = 1.3 Determine the minimum bolt diameter that may be used in the connection? In correct way

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter5: Beams

Section: Chapter Questions

Problem 5.2.1P

See similar textbooks

Similar questions

The five-bolt connection shown must support an applied load of P = 300 N. The thickness of the axial member: = 1.5 mm. and the width = 18 mm If the ultimate shear stress in the bolts must be limited to 265 MPa with F.O.S = 3.7 . And the ultimate normal stress in the axial member = 250 MPa, with F.O.S = 2.8 , And the ultimate bearing stress in the axial member = 110 MPa, F.O.S = 2.5 Determine the minimum bolt diameter that may be used in the connection
A 20-mm-thick plate is bolted to the flange of a T-beam to form a 200 mm 20 mm built-up beam. If the beam is subjected to a vertical shear force of V = 200 kN, determine (a) the maximum shear stress in the beam, 10 mm 300 mm (b) the required spacing s of the bolts. The diameter of each bolt is 19 mm, and the allowable average shear stress in the bolts is 140 MPa. 10 mm
Six rivets are used in the connection shown in the figure. If both P=50KN, what is the minimum diameter rivet is necessary so as not exceed the 70MPa allow shearing stress? What thickness of plate is required so as not exceed a bearing stress of 140MPA? p= 50 80 mm 80 mm 100 mm
The five-bolt connection must support an applied load of P = 149 kips. If the average shear stress in the bolts must be limited to 50 ksi, what is the minimum bolt diameter that may be used for this connection? P Answer: d = i in.
For the given riveted connection shown, having the allowable stresses: Fy = 248 MPa Fy = 150 MPa (shear stress) Tensile stress=0.60 Fy Bearing stress = 1.35 Fy Rivet hole has a diameter 2mm greater than the rivet diameter. The main plate has a width of 300mm and a thickness of 20mm. Determine the diameter of rivets such the shear capacity of the rivets is equal to its bearing capacity. Also, compute the maximum value of P so as not to exceed the allowable tensile stress of plates. P- O JAK O O 300 mm -P/2 -P/2
For the given riveted connection shown, having the allowable stresses: Fy = 248 MPa Fy = 150 MPa (shear stress) Tensile stress = 0.60 Fy Bearing stress = 1.35 Fy Rivet hole has a diameter 2mm greater than the rivet diameter. The main plate has a width of 300mm and a thickness of 20mm. Determine the diameter of rivets such the shear capacity of the rivets is equal to its bearing capacity. Also, compute the maximum value of P so as not to exceed the allowable tensile stress of plates. 300 mm t/2 -P/2 P- -P/2
For the connection shown, the bolt diameter is d = 15 mm. The average shear stress in the bolts must be limited to 210 MPa. Determine the maximum load P that may be applied to the connection based on the shear strength of the bolts.
For the rivet connection shown in figure 2-4, the allowable shearing stress in the 25mm rivets is 140 MPa. Assume the plates are adequate to transmit the load to the rivets. P= 60 KN. a) Determine the shearing stress in the most stressed rivet. b) Determine the maximum allowable value of P. c) If P=80 KN, determine the minimum diameter of rivets. USE NSCP 2015. Thanks.
A plate with width of 300mm and thickness of 20mm is to be connected between two plates 12mm thick with same width by 4-25mm diameter rivets a shown. The rivet holes have a diameter 2mm larger than the rivet diameter. The plate is A36 steel with yield strength Fy=248 Mpa and Fu-400MPa. The rivets have nominal shear stress capacity of 165MPa. O 803 O 1490 • Determine maximum load (P1) that can be applied without exceeding design tensile stress in plates (consider yielding and rupture of plates ONLY) in KN O 1180 O 1340 ο ο ο ο ο P3 O 1968 O 590 O 670 O 893 O 707 OO 150 O 1180 P1 P2
The wall bracket show below carries a load of P Kip. the allowable tensile in the eye bar is 20 ksi, and the allowable shear stress in the pin is 12 ksi. Select: a) The diameter of the eye bard b) the diameter of the pin at A which is double shear c) the diameter of the pin at B which is single One eye-bar 6 ft P kip 4 ft
Determine the length of tension anchorage required for the 36 mm diameter plain mild steel reinforcing bars in the canrilever of figuer below. The charactersitic material strengths are feu-30N/mm² and fy=250KN. The ultimate anchorage bond stress. Stress, fou-1.5N/mm² Anchorage length R25 bars
10/10 find the tensile stress in upper plate in section 3-3 80 kN 80 kN 8-bolt DIA. 10 MM 80 kN 80 kN 8-bolt DIA. 10 MM 10 MPа О 12.5 MPa 15 MPa 8.5 MPa O no one O ---.. O- O O 300mm 8 mm