The figure shows an electron passing between two charged metal plates that create a 106 N/C vertical electric field perpendicular to the electron’s original horizontal velocity. (These can be used to change the electron’s direction, such as in an oscilloscope.) The initial speed of the electron is 3.2 × 106 m/s , and the horizontal distance it travels in the uniform field is 4.4 cm. What is its vertical deflection in m?  What is the vertical component of its final velocity in m/s?  At what angle does it exit in degrees? Neglect any edge effects.

Q: Two horizontal parallel plates are seperated by a distance of 175mm creating an electric field of…

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Q: A simple and common technique for accelerating electrons is shown in the figure below, where there…

A: Electric field strength in between the plates E=2.32*104N/C which makes the electrons go out the…

Q: The figure shows an electron passing between two charged metal plates that create a 108 N/C vertical…

A:

Q: A proton enters a region of uniform electric field of magnitude 79.9 N/C with an initial velocity of…

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Q: A particle leaves the origin with a speed of 3.5 106 m/s at 28 degrees to the positive x axis. It…

A: Given, Speed of the particle, v = 3.5×106 ms Electric field is along the positive y-direction, when…

Q: Two tiny spheres of mass 9 mg carry charges of equal magnitude, 72 nC, but opposite sign. They are…

A: Given,Mass of the sphere, m = 9 mg = 9 ×10-6 kgmagnitude of charge, Q = 72 nC = 72 ×10-9 Clength of…

Q: An electron has an initial velocity of 4.24 x 106 m/s in a uniform 4.51 x 105 N/C strength electric…

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Q: ente

A: Given: Initial velocity is 58 km/s Magnitude is 52 N/C Speed of electron is 1.3 ns

Q: Protons are projected with an initial speed v0 = 9,450 m/s into a region where a uniform electric…

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Q: Charge q₁ = 2.50 nC is at x₁ = 0 and charge q2 = 5.50 nC is at x₂ = 5.00 m. At what point between…

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Q: Air breaks down (loses its insulating quality) and sparking results if the field strength is…

A: Answer:-    B) 5.27*10^20 mm

Q: Two horizontal parallel plates are seperated by a distance of 175mm creating an electric field of…

A:

Q: An electron with a speed of v=4×107 m/s enters an electric field of magnitude E=5×103 N/C, traveling…

A:

Q: A proton is initially moving to the right when it enters a uniform electric field directed upwards.…

A: As the direction of the electric field is in the upward direction. Therefore, the direction of the…

Q: An old TV has a cathode ray tube that has an electric potential difference of 1.60x10^4 V across…

A: Given Potential difference=1.6*10^4 V d=12 cm q=charge on an electron=-1.6*10^-19 C

Q: A proton (q=e= 1.602x10-19 C, m=1.67x10-27 kg) goes through a small hole in a negatively charged…

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Q: An electron has an initial velocity of 6.00 ✕ 106 m/s in a uniform 9.00 ✕ 105 N/C strength electric…

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Q: Figure  shows an electron passing between two charged metal plates that create an 100 N/C vertical…

A: Vertical electric field, E =  100 N/C  The initial speed of the electron v0 = 3.00×106 m/s  The…

Q: A positron (positive electron) has an initial speed of 9.555 m/s when it enters a region where a…

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Q: An electron with speed 2.15×107 m/sm/s is traveling parallel to a uniform electric field of…

A: Ignoring relativistic effects we can solve the above question in the following method:-

Q: The figure below shows an electron passing between two charged metal plates that create an 100 N/C…

A:

Q: SUZ The figure shows an electron passing between two charged metal plates that create a 108 N/C…

A: See below

Q: an electron is projected with an initial speed vo=2.00*10^6 m/s into the uniform field between…

A:

Q: wo horizontal parallel plates are separated by a distance of 168mm creating an electric field of…

A: Given: The electric field is 29µN/C. The separation between plates is 168 mm. The initial speed of…

Q: An electron is accelerated at 106m/s2 by an electric field. What is the direction and magnitude of…

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Q: 4. At some instant the velocity of an electron moving between two charged parallel plates is given…

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Q: The electric field at a point in space is E = (700 I +600 J). What is the magnitude of the electrons…

A: Given that,  Electric field, E = 700i + 600j We know that charge of electron and proton is, Q = 1.6…

Q: The figure shows an electron passing between two charged metal plates that create a 108 N/C vertical…

A: The Given That: Electric Field, E=108 N/C The Horizontal Velocity, Vx=3.1×106 m/s Horizontal…

Q: An electron is projected with an initial speed v0 = 1.40x105 m/s into the uniform field between the…

A: Given data:Initial horizontal  speed of the electron, v= 1.4× 10⁶ m/sDistance travelled by the…

Q: An electron with a speed of 3.60 x 108 cm/s in the positive direction of an x axis enters an…

A:

Q: The figure below shows an electron passing between two charged metal plates that create an 100 N/C…

A:

Q: particle (q = 5 mC, m = 20 g) has a speed of 13 m/s when it enters a region where the electric field…

A: Given data, Charge q=5 mC. Mass m=20 gram. Electric field E= 43 N/c. Initial speed u = 13 m/s,

Q: An electron with a speed of 6.19 x 108 cm/s in the positive direction of an x axis enters an…

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Q: An electron is projected with horizontal velocity of magnitude vo into a constant downward electric…

A:

Q: A simple and common technique for accelerating electrons is shown in the figure below, where a…

A: We have givenElectric field strength, E=2.33×104 N/C

Q: Two horizontal parallel plates are separated by a distance of 172x10^-3 m creating an electric field…

A: The second equation of motion is  s= u t + 0.5 at2 where, s is the distance,  u is the initial…

Q: A proton, mass 1.67 x 10-27 kg, is projected horizontally midway between two parallel plates that…

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Q: A proton is ejected into a uniform horizontal field. The electric field is given by E (2.0 10-19…

A: Electric field, E=2×10-10 N/C i^ Initial velocity, vo→=5×105(m/s) j^ Time t=3 s

Q: 3. A proton is in a uniform electric field directed to the left. It is released from rest and moves…

A: Write the given values with the suitable variables. u=0 m/ss=10 cm=0.1 mK=0.005 J Here, u is the…

Q: Air breaks down (loses its insulating quality) and sparking results if the field strength is…

A:

Q: In a typical television or in an older computer picture tube (CRT), the electrons that strike the…

A: To find the electric field strength use the formula: E=dVdx Given: The potential difference,…

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.