A proton (q=e= 1.602x10-19 C, m=1.67x10-27 kg) goes through a small hole in a negatively charged metal plate with an initial velocity of v 4.59x105 m/s at =11 degrees above the horizontal. The field above the plate has a magnitude of E= 3.42x103 N/C. a) What is the acceleration of the proton? b) How much time does it take from going through the small whole til it hits the plate? c) How far in meters will the proton travel horizontally before it hits the plate?

An electron has an initial velocity of 10.0 × 106 m/s in a uniform 3.00 x 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity. (a) What is the direction of the electric field? same direction as the electron's initial velocity V (b) How far does the electron travel before coming to rest? m (c) How long does it take the electron to come to rest? S (d) What is the electron's speed when it returns to its starting point? m/s

An electron with a speed of 6.19 × 108 cm/s in the positive direction of an x axis enters an electric field of magnitude 1.23 × 10³ N/C, traveling along a field line in the direction that retards its motion. (a) How far will the electron travel in the field before stopping momentarily, and (b) how much time will have elapsed? (c) If the region containing the electric field is 5.29 mm long (too short for the electron to stop within it), what fraction of the electron's initial kinetic energy will be lost in that region? (a) Number (b) Number (c) Number 0.08868 2.9E-8 M Units Units m S Units This answer has no units

An electron is placed in a uniform electric field of 32nN/C directed north created by two horizontal parallel plates that are 131fm apart. The electron accelerates from rest, starting at the negative plate. What is the net force and acceleration acting on the electron? How long did it take the electron to get from one side of the plate to the other?