The figure shows a glass cylinder of radius 6.8 cm, partially filled with oil of density 0.87 × 10³ kg/m³. . Floating freely on top with no oil leaking around the sides, a 2.8-kg wooden disk supports a 0.5-kg potato. Calculate the gauge pressure in psi at 13.6 cm below the surface of the oil. (1 psi = 6.895 kPa) %3D pooM psi (Note the units!) %3D = d

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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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8
7.
V
%24
因/ロ
6)
f8
E3
9F
f5
SNSV
直。
= d
psi (Note the units!)
%3D
poom
surface of the oil. (1 psi = 6.895 kPa)
Calculate the gauge pressure in psi at 13.6 cm below the
%3D
sides, a 2.8-kg wooden disk supports a O.5-kg potato.
partially filled with oil of density 0.87 × 103 kg/m³.
The figure shows a glass cylinder of radius 6.8 cm,
Floating freely on top with no oil leaking around the
Transcribed Image Text:8 7. V %24 因/ロ 6) f8 E3 9F f5 SNSV 直。 = d psi (Note the units!) %3D poom surface of the oil. (1 psi = 6.895 kPa) Calculate the gauge pressure in psi at 13.6 cm below the %3D sides, a 2.8-kg wooden disk supports a O.5-kg potato. partially filled with oil of density 0.87 × 103 kg/m³. The figure shows a glass cylinder of radius 6.8 cm, Floating freely on top with no oil leaking around the
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