The figure shows a cantilevered beam, subjected to a uniformly distributed (rectangular) 40 N/m force along the section DE, a 50 N point force at point C, and a 200 N·m couple moment. a. Write the shear-force and bending-moment equations as a function of distance, x, measured from the leftmost point, A, for the entire beam. b. Using your shear-force and bending-moment equations, calculate the shear force and bending moment at x = 2 m and x = 5 m. 200 N·m 2.5 m 50 N CV D 1m 40 N/m 2.5 m E B 2 m

The figure shows a cantilevered beam, subjected to a uniformly distributed (rectangular) 40 N/m force along the section DE, a 50 N point force at point C, and a 200 N·m couple moment. a. Write the shear-force and bending-moment equations as a function of distance, x, measured from the leftmost point, A, for the entire beam. b. Using your shear-force and bending-moment equations, calculate the shear force and bending moment at x = 2 m and x = 5 m. 200 N·m 2.5 m 50 N CV D 1m 40 N/m 2.5 m E B 2 m

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter4: Shear Forces And Bending Moments

Section: Chapter Questions

Problem 4.5.27P: The simple beam ACE shown in the figure is subjected to a triangular load of maximum intensity q0=...

See similar textbooks

Similar questions

At a full d raw, an archer applies a pull of 130 N to the bowstring of the bow shown in the figure. Determine the bending moment at the midpoint of the bow.
The simple beam ACE shown in the figure is subjected to a triangular load of maximum intensity q0= 200 lb/ft at a = 8 ft and a concentrated moment M = 400 Ib-ft at A. Draw the shear-force and bending-moment diagrams for this beam, Find the value of distanced that results in the maximum moment occurring at L/2. Draw the shear-force and bending-moment diagrams for this case. Find the value of distance a for which Mmaxis the largest possible value.
A beam of length L is designed to support a uniform load of intensity q (see figure). If the supports of the beam are placed at the ends, creating a simple beam, the maximum bending moment in the beam is qL2/8. However, if the supports of the beam are moved symmetrically toward the middle of the beam (as shown), the maximum bending moment is reduced. Determine the distance a between the supports so that the maximum bending moment in the beam has the smallest possible numerical value. Draw the shear-force and bending-moment diagrams for this condition. Repeat part (a) if the uniform load is replaced with a triangularly distributed load with peak intensity q0= q at mid-span (see Fig. b).
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a=11.0 ft, b-4.5 ft, c= 7.5 ft, w = 4 kips/ft and M = 250 kip-ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. 27 W Ay a b Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) W M a B M C b C C₂ C -X
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. Place the origin at point A. Let a=4.00 m, b=5.25 m, c= 2.50 m, P = 26kN and M = 160kN-m. Construct the shear-force and bending-moment diagrams. Use the bending-moment diagram to determine the maximum positive bending moment, Mmax, pos, and the maximum negative bending moment, Mmax, neg.
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a=4.00 m, b=5.25 m, c= 2.75 m, P = 36kN and M = 195kN-m. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. A Answers: Ay= Cy= b Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) i i a M a B M B b kN 2 C KN C Cy C P с X P
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a=14.0 ft, b=3.0 ft, c= 7.0 ft, w = 9 kips/ft and M = 300 kip-ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. " " Answers: Ay= Cy= b Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) i W i a W M a B M B ес b kips kips с Cy с X с -X
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a=12.0 ft, b=6.5 ft, c= 7.0 ft, w = 7 kips/ft and M = 230 kip-ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise.Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) Determine the shear force acting at each of the following locations:(a) x = 0+ ft (i.e., just to the right of support A)(b) x = 12.0 ft (i,e., at point B)(c) x = 18.5- ft (i.e., just to the left of the support C)(d) x = 18.5+ ft (i.e., just to the right of the support (C)(e) x = 24.5 ftNote that x = 0 at support A. Determine the bending…
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a=1.50 m, b=5.00 m, PA = 75kN, and PC = 90kN. Construct the shear-force and bending-moment diagrams. Determine the bending moment acting at each of the following locations:(a) x = 1 m(b) x = 1.50 m (i.e., at support B)(c) x = 4 m(d) x = 6.50 m (i.e., at point C)(e) x = 7.00 m
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a=1.50 m, b=5.00 m, PA = 75kN, and PC = 90kN. Construct the shear-force and bending-moment diagrams. Determine the shear force acting at each of the following locations:(a) x = 1 m(b) x = 4 m(c) x = 7.00 m
The figure shows a cantilevered beam, subjected to a uniformly distributed (rectangular) 40 N/m force along the section DE, a 50 N point force at point C, and a 200 Nm couple moment. a. Write the shear-force and bending-moment equations as a function of distance, x, measured from the leftmost point, A, for the entire beam. b. Using your shear-force and bending-moment equations, calculate the shear force and bending moment at x = 2 m and x = 5 m. 200 N·m A 2.5 m 50 N CV D 1 m 40 N/m ↓↓↓ 2.5 m E B 2 m
The simply supported beam is subjected to the force F = 700 N and the uniform distributed load with intensity w = 150 N/m. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(r) and M(x). Take a = 0 at point A. 19 F a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 5.2 m 2.6 m 3.12 m Support Reactions The reaction at A is N. The reaction at D is N. Shear Force and Bending Moment Equations In section AB: V(x)= N and M(x)= N-m. In section BC: v(x)- N and M(x)= N-m. In section CD: V(x)- N and M(x)= N-m. A