The figure below shows how a bleeder resistor (R = 246 kN) is used to discharge a capacitor (C = 63.7 µF) after anelectronic device is shut off, allowing a person to work on the electronics with less risk of shock.Electroniccircuit(a) What is the time constant?S(b) How long will it take to reduce the voltage on the capacitor to 0.100% of its full value once discharge begins?S(c) If the capacitor is charged to a voltage Vo through a 133 2 resistance, calculate the time it takes to rise to0.865V, (this is about two time constants).

We will use the RC circuit formulation in this problem,

The figure below shows how a bleeder resistor (R = 246 kN) is used to discharge a capacitor (C = 63.7 µF) after an electronic device is shut off, allowing a person to work on the electronics with less risk of shock. Electronic IR circuit (a) What is the time constant? (b) How long will it take to reduce the voltage on the capacitor to 0.100% of its full value once discharge begins? (c) If the capacitor is charged to a voltage Vo through a 133 N resistance, calculate the time it takes to rise to 0.865V, (this is about two time constants). ww

The figure below shows how a bleeder resistor (R = 246 kN) is used to discharge a capacitor (C = 63.7 µF) after an electronic device is shut off, allowing a person to work on the electronics with less risk of shock. Electronic IR circuit (a) What is the time constant? (b) How long will it take to reduce the voltage on the capacitor to 0.100% of its full value once discharge begins? (c) If the capacitor is charged to a voltage Vo through a 133 N resistance, calculate the time it takes to rise to 0.865V, (this is about two time constants). ww