The figure below is a system consisting of two masses MA = 1.82 kg and MB = 3.6 kg, whose distance from the pore axis is R₁ = R₂ = 15 cm, while the angular positions are 0₁ = 30° and 0 = 150° . Determine the weight and position of the balancing mass placed on planes C and D if the distance from the axis RC = RD = 15 cm.

The plant in the picture has mass of 29 kg, and is hanging at a distance of 1.4 meters from the wall. The horizontal rod has mass of 6.2 kg. Assume that its weight is evenly distributed, therefore it can be treated as a single force at the center of mass. The rod is 2 meters long, and there is a cable at a 23° angle supporting it at the end. Center of mass of rod from the point = 2/2=1m Using the wall as the axis of rotation, find the magnitude of the downward torque, from both the weight of the rod and the weight of the plant. t=458.64Nm a.The downward torque is balanced by the upward torque from the force of tension. Find the magnitude of the force of tension. T=?N b.F is the contact force between the rod and the wall. Using the other horizontal force in the problem, find the horizontal component of F (the normal force) that must be present for the rod to be at equilibrium. Fx=?N c.There is a vertical force from a component of the tension, but this is not enough to balance the…

The position of the head and neck and the forces acting on the head are shown in the figure. The center of gravity of the head of mass m=9 kg is located at point C. The joint reaction force of F J = 150 N, which makes an angle of α = 30° with the vertical from the point B, is acting on the skull by the neck extensor muscles. The center of the atlantooccipital joint is located at point B. For this flexion position of the head, the neck muscle force FM, which makes an angle of γ with the horizontal from the point A , is effective . (Take the gravitational acceleration g as 9.81 m/s 2. ) Accordingly; a)   Calculate the angle γ of the muscle force F M with the horizontal. b)   Calculate the muscle strength F M. (Write your result in N units.)

Three identical 8.60-kg masses are hung by three identical springs, as shown in the figure. (Figure 1) Each spring has a force constant of 5.90 kN/m and was 11.0 cm long before any masses were attached to it. Make a free-body diagram for the top mass. Draw the vectors starting at the black dot at the center of the top mass.