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- The wheels, axle, and handles of a wheelbarrow weigh W = 55 N. The load chamber and its contents weigh WL = 623 N. The drawing shows these two forces in two different wheelbarrow designs. To support the wheelbarrow in equilibrium, the man’s hands apply a force to the handles that is directed vertically upward. Consider a rotational axis at the point where the tire contacts the ground, directed perpendicular to the plane of the paper. Find the magnitude of the man’s force for both designs.A 6-m long ladder has a mass of 16 kg, and its center of gravity is 2.4 m from the bottom along the ladder. The ladder is resting on a 5° upward sloping floor at A and on a wall inclined to the right at 5° from the vertical at B, so that it makes an angle of 60° with the horizontal.How far up along the ladder can a 79-kg man climb before the ladder is on the verge of slipping? The angle of friction at all contact surfaces is 15°. Also determine the total reaction at A and B in Newton. Note: Point A is at the left of point B.Q3/ A shaft has three eccentric of mass 1 kg each. The central plane of the eccentrics is 50 mm apart. The distances of the centers from the axis of rotation are 20, 30 and 20 mm and their angular positions are 120 apart. If the shaft is balanced by adding two niasses at a radius of 70 mm and at a distance 100 mm from the central plane of the middle eccentric, find the amount of the masses and their angular positions.
- A man holds a 187-N ball in his hand, with the forearm horizontal (see the figure). He can support the ball in this position because of the flexor muscle force M, which is applied perpendicular to the forearm. The forearm weighs 18.5 N and has a center of gravity as indicated. Find (a) the magnitude of M and the (b) magnitude and (c) direction (as a positive angle counterclockwise from horizontal) of the force applied by the upper arm bone to the forearm at the elbow joint. Upper arm bone Elbow joint 0.0510 m+ Flexor muscle -0.0890 m -0.330 m-Question 5- find the سا mg-2 2N that act at an resultant of forces 2, √3, 5, √3 and angular point of a regular Hexagon towards other angular points taking arder. Aus R=10N x=60 Question 6- A string ABC of to two points A and C at the same level. A string ABC of length 50cm is tied A smooth ring of weight 500 N which can slide along the string at B, 30cm away from A along the string and pulley by a horizontal force Pas shown in figure 3. If point B is 15cm beforce of AC magnitude of P while tensions in the Determine the on both side of B'are same string of th Aus → T = 900 NThe figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The total weight of the leg and the cast is W=250 N. The distance between the points A and B where the cables are attached to the leg is given as L=100 cm and the angle of the leg with the horizontal is γ=6°. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=40°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. Response
- A window cleaner is pulling himself up to a pulley that consists of two disks welded together as shown. The person is currently pulling straight down on the rope in his hands with a force of magnitude 580.4 N. The other rope is also vertical and is attached to the person's center of mass. The person's mass is 74.2 kg, the pulley's total moment of inertia is 395 kgm2, the radius of the small disk is 0.39 m, and the radius of the big disk is 0.73 m.What is the magnitude of the acceleration of the person's center of mass?Find the horizontal force , P required to turn the wheel weighing 500 over the block 10cm high if radius of the wheel is 25 cmA man on the wire singing "Man on a Wire" while practicing for his circus show has reached the center of the rope, creating a dip on the center angled at 67.87 degrees. If the mass of the man is 42.23 kg and the tension force that can be handled by the wire is 301.26 N, would the wire break? Show the tension caused by the man hanging on the wire. (with illustration)
- A man holds a 192-N ball in his hand, with the forearm horizontal (see the figure). He can support the ball in this position because of the flexor muscle force M→, which is applied perpendicular to the forearm. The forearm weighs 18.5 N and has a center of gravity as indicated. Find (a) the magnitude of M→ and the (b) magnitude and (c) direction (as a positive angle counterclockwise from horizontal) of the force applied by the upper arm bone to the forearm at the elbow joint. For the direction I know the units is degrees, but I have tried using the answer from b, and it is not correct.2.Find the complete placement reaction in the image below Responso 12 kN 3 m 3 m D 4 m 8 m 15 kN 4 m 20 kN/m A BI-Find box for the given Plane, where by =120m, d=25m, bz=25m, d2=100m, b3=80m & d3=25 m (Enter only the values in the boxes by referring the unit given in brackets. Also upload your hand written answers in the link provided) b2 dz di bị The value of X= (unit in m) The value of Y= (unit in m) The moment of inertia for sec 1 = lyyi = (unit in m) The moment of inertia for sec 2 = lyy2 = (unit in m4) The moment of inertia for sec 3 = lyya = (unit in m4) The moment of inertia of the given plate = lyy = (unit in m)