Answer please The exergy of 0.4 kg of wet steam at 0.1 bar and 0.85 quality iskJ.(Assume dead state of 1 bar and 300 K)Data:At 1 bar, 300 Kh. = 113.2 kJ/kg; s, = 0.395 kJ/kgKAt 0.1 bar, 0.85 quality192 kJ/kg; h, = 2582 kJ/kgh,=$ 0.649 kJ/kgK; s, 8.148 kJ/kgK(a) 48.8 kJ(c) 112.6 kJ%3D(b) 57.9 kJ(d) 93.8 kJ

Given that ; The mass of wet steam is mw=0.4 kg. The pressure of wet steam is P0=0.1 bar. The…

The exergy of 0.4 kg of wet steam at 0.1 bar and 0.85 quality is (Assume dead state of 1 bar and 300 K) Data: At 1 bar, 300 K ho = 113.2 kJ/kg; s = 0.395 kJ/kgK At 0.1 bar, 0.85 quality h, = 192 kJ/kg; h=2582 kJ/kg = 0.649 kJ/kgK; s = 8.148 kJ/kgk (a) 48.8 kJ (b) 57.9 kJ (d) 93.8 kJ (c) 112.6 kJ

The exergy of 0.4 kg of wet steam at 0.1 bar and 0.85 quality is (Assume dead state of 1 bar and 300 K) Data: At 1 bar, 300 K ho = 113.2 kJ/kg; s = 0.395 kJ/kgK At 0.1 bar, 0.85 quality h, = 192 kJ/kg; h=2582 kJ/kg = 0.649 kJ/kgK; s = 8.148 kJ/kgk (a) 48.8 kJ (b) 57.9 kJ (d) 93.8 kJ (c) 112.6 kJ

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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