The equilibrium constant, Kp, for the following reaction is 9.52x102 at 350 K: CH4(g) + CCl4(g)2CH2Cl2(g) Calculate the equilibrium partial pressures of all species when CH4 and CCI4, each at an intitial partial pressure of 0.879 atm, are introduced into an evacuated vessel at 350 K. P CHA atm atm CC atm P = CH2Cl₂ P Submit Answer Retry Entire Group 1 more group attempt remaining

Chemistry: An Atoms First Approach
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Chapter16: Spontaneity, Entropy, And Free Energy
Section: Chapter Questions
Problem 83AE: Consider the following system at equilibrium at 25C: PCl3(g)+Cl(g)PCl5(g)G=92.50KJ What will happen...
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The equilibrium constant, Kp, for the following reaction is 9.52x102 at 350 K:
CH4(g) + CCl4(g)2CH2Cl2(g)
Calculate the equilibrium partial pressures of all species when CH4 and CCI4, each at an intitial partial pressure of 0.879 atm, are
introduced into an evacuated vessel at 350 K.
P CHA
atm
atm
CC
atm
P
=
CH2Cl₂
P
Submit Answer
Retry Entire Group 1 more group attempt remaining
Transcribed Image Text:The equilibrium constant, Kp, for the following reaction is 9.52x102 at 350 K: CH4(g) + CCl4(g)2CH2Cl2(g) Calculate the equilibrium partial pressures of all species when CH4 and CCI4, each at an intitial partial pressure of 0.879 atm, are introduced into an evacuated vessel at 350 K. P CHA atm atm CC atm P = CH2Cl₂ P Submit Answer Retry Entire Group 1 more group attempt remaining
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