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The equilibrium constant, Ke, for the following reaction is 1.80x104 at 298 K. NH4HS(s) =NH3(g) + H2S(g) Calculate the equilibrium concentration of H2S when 0.457 moles of NH4HS(s) are introduced into a 1.00 L vessel at 298 K. [H2S] = M

The equilibrium constant, Ke, for the following reaction is 1.80x104 at 298 K. NH4HS(s) =NH3(g) + H2S(g) Calculate the equilibrium concentration of H2S when 0.457 moles of NH4HS(s) are introduced into a 1.00 L vessel at 298 K. [H2S] = M

Physical Chemistry
Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter5: Introduction To Chemical Equilibrium
Section: Chapter Questions
Problem 5.41E: Write the equilibrium constant expression for each reaction in terms of activities, simplifying...
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The equilibrium constant, Ke, for the following reaction is 1.80x104 at 298 K. NH4HS(s) =NH3(g) + H2S(g) Calculate the equilibrium concentration of H2S when 0.457 moles of NH4HS(s) are introduced into a 1.00 L vessel at 298 K. [H2S] = M %3D
Transcribed Image Text:The equilibrium constant, Ke, for the following reaction is 1.80x104 at 298 K. NH4HS(s) =NH3(g) + H2S(g) Calculate the equilibrium concentration of H2S when 0.457 moles of NH4HS(s) are introduced into a 1.00 L vessel at 298 K. [H2S] = M %3D
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