Use the data given below to construct a Born-Haber cycle to determine the enthalpy of sublimation for Xornon (Xo). Answer in kJ/mol. Reaction/Process AH°(kJ/mol) Part 1: 5751 Xo(s)Xo(g) Submit Answer Previous Incorrect. Tries 12/99 Tries Xo(g) Xo+(g) + 590 e Xo+(g) Xo2+(g) 1010 + e 2 0(g) 02(g) -498 O(g) + er – -141 O (g) + e- -→ o2 (g) 878 Xo(s) + V2 02(g) Xo0(s) -635 Xo (g) + 02 (g) XoO(s) -3414 Part 2: What is the enthalpy of solution given enthalpy of hydration for Xo²+ is -1754 kJ/mol and 02- is -933 kJ/mol? kJ/mol Submit Answer Tries 0/99

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Born-Haber cycle; I don’t know how to formulate it for this reaction.
Use the data given below to construct a Born-Haber cycle to determine the enthalpy of sublimation for Xornon (Xo). Answer in kJ/mol.
Reaction/Process
AH°(kJ/mol)
Part 1: 5751
Xo(s)Xo(g)
Submit Answer
Previous
Incorrect. Tries 12/99
Tries
Xo(g)
Xo+(g) +
590
e
Xo+(g)
Xo2+(g)
1010
+ e
2 0(g) 02(g)
-498
O(g) + er –
-141
O (g) + e- -→
o2 (g)
878
Xo(s) + V2 02(g)
Xo0(s)
-635
Xo (g) + 02 (g)
XoO(s)
-3414
Part 2: What is the enthalpy of solution given enthalpy of hydration for Xo²+ is -1754 kJ/mol and 02- is -933 kJ/mol?
kJ/mol
Submit Answer
Tries 0/99
Transcribed Image Text:Use the data given below to construct a Born-Haber cycle to determine the enthalpy of sublimation for Xornon (Xo). Answer in kJ/mol. Reaction/Process AH°(kJ/mol) Part 1: 5751 Xo(s)Xo(g) Submit Answer Previous Incorrect. Tries 12/99 Tries Xo(g) Xo+(g) + 590 e Xo+(g) Xo2+(g) 1010 + e 2 0(g) 02(g) -498 O(g) + er – -141 O (g) + e- -→ o2 (g) 878 Xo(s) + V2 02(g) Xo0(s) -635 Xo (g) + 02 (g) XoO(s) -3414 Part 2: What is the enthalpy of solution given enthalpy of hydration for Xo²+ is -1754 kJ/mol and 02- is -933 kJ/mol? kJ/mol Submit Answer Tries 0/99
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