The equilibrium constant, Ke, for the following reaction is 1.80 x 104 at 298 K. NH4HS(9) NH3(g) + H₂S(g) Calculate the equilibrium concentration of H₂S when 0.322 moles of NH4HS(s) are introduced into a 1.00 L vessel at 298 K. [H₂S] = M Submit Answer Retry Entire Group 9 more group attempts remaining ТОГ

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The equilibrium constant,
Ke, for the following reaction is
1.80 x 104 at 298 K.
[Review Topics]
[References]
Use the References to access important values if needed for
NH4HS(9) NH3(g) + H₂S(9)
Calculate the equilibrium concentration of
H₂S when 0.322 moles of
NH4HS(s) are introduced into a 1.00 L vessel at 298 K.
[H₂S] =
M
Submit Answer
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NOV
30
Le...
The equilib
tv
Retry Entire Group 9 more group attempts remaining
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M
Transcribed Image Text:q The equilibrium constant, Ke, for the following reaction is 1.80 x 104 at 298 K. [Review Topics] [References] Use the References to access important values if needed for NH4HS(9) NH3(g) + H₂S(9) Calculate the equilibrium concentration of H₂S when 0.322 moles of NH4HS(s) are introduced into a 1.00 L vessel at 298 K. [H₂S] = M Submit Answer Show Hint NOV 30 Le... The equilib tv Retry Entire Group 9 more group attempts remaining Email In M
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