Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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- Consider the following reaction where K. = 1.29×102 at 600 K. CoC2(g) CO(g) + Cl(g) A reaction mixture was found to contain 0.107 moles of COC,(g), 4.17x102 moles of CO(g), and 4.11×102 moles of Cl(g), in a 1.00 liter container. Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium? The reaction quotient, Qe equals The reaction A. must run in the forward direction to reach equilibrium. B. must run in the reverse direction to reach equilibrium. C. is at equilibrium.arrow_forwardSuppose a 500. mL flask is filled with 0.60 mol of Br,, 0.10 mol of OCl, and 1.5 mol of BrOCl. The following reaction becomes possible: Br, (g) +OCl, (g) - - BrOC1(g) +Brci(g) The equilibrium constant K for this reaction is 0.349 at the temperature of the flask. Calculate the equilibrium molarity of BrOCl. Round your answer to two decimal places.arrow_forward3. For the reaction SO2(g) + NO2(g) 2 NO(g) + SO3(g), Ko = 85.0 at 4.60 x 102 °C. A reaction is started with 0.0500 M of both reactants (Note, initially no products). a) Calculate the equilibrium concentration in M of all species. (If you correctly set-up the ICE chart for this problem, you will see the equilibrium constant expression is a perfect square & so the quadratic formula is not needed. If yours is not a perfect square, check your work.)arrow_forward
- [Review Topics] [References] Use the References to access important values if needed for this question. The equilibrium constant, Kc, for the following reaction is 7.00 × 10-5 at 673 K. NH4I(s) NH3(g) + HI(g) If an equilibrium mixture of the three compounds in a 6.73 L container at 673 K contains 1.48 mol of NH4I(s) and 0.467 mol of NH3, the number of moles of HI present is mol. Submit Answer Q F4 % 5 Show Hint F5 ^ 6 Y Retry Entire Group 8 more group attempts remaining C F6 & 7 F7 * 8 F8 ( 9 F9 O ) O F10 P F11 Previous + F12 Next> deletearrow_forwardSuppose a 250. mL flask is filled with 0.90 mol of Cl₂, 1.2 mol of HCl and 2.0 mol of CC14. The following reaction becomes possible: Cl2(g) + CHCl3(g) → HCl(g) + CCl4(g) The equilibrium constant K for this reaction is 0.702 at the temperature of the flask. Calculate the equilibrium molarity of CHC13. Round your answer to two decimal places.arrow_forwardThe equilibrium constant, Kc , for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g)If an equilibrium mixture of the three compounds in a 5.09 L container at 548 K contains 3.65 mol of NH4Cl(s) and 0.368 mol of NH3, the number of moles of HClpresent is moles.arrow_forward
- The equilibrium constant, Kc , for the following reaction is 1.80×10-4 at 298 K. NH4HS(s) NH3(g) + H2S(g)If an equilibrium mixture of the three compounds in a 6.16 L container at 298 K contains 2.05 mol of NH4HS(s) and 0.359 mol of NH3, the number of moles of H2Spresent is moles.arrow_forwardThe equilibrium constant, K, for the following reaction is 5.00x10-2 at 642 K. COCI2(g) : =CO(g) + Cl2(g) An equilibrium mixture of the three gases in a 5.49 L container at 642 K contains 0.288 M COCI2, 0.120 M CO and 0.120 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 11.9 L? [COCI2] = [CO] [Cl2] M ΣΣΣ Il||arrow_forwardThe equilibrium constant, Kc, for the following reaction is 0.0952 at 350. K. CH₁ (g) + CCl4 (g) 2CH₂Cl2 (g) Calculate the equilibrium concentrations of reactants and product when 0.205 moles of CH4 and 0.205 moles of CCL are introduced into a 1.00 L vessel at 350. K. [CH4] = | M [CC14] = [CH₂ Cl₂] = M Marrow_forward
- The equilibrium constant, Kp , for the following reaction is 1.04×10-2 at 548 K.NH4Cl(s) NH3(g) + HCl(g)If an equilibrium mixture of the three compounds in a 6.28 L container at 548 K contains 1.00 mol of NH4Cl(s) and 0.224 mol of NH3(g), the partial pressure of HCl(g) is atm.arrow_forwardThe equilibrium constant, K, for the following reaction is 9.23×10-3 at 304 K. NH4HS(s) =NH3(g) + H2S(g) An equilibrium mixture in a 18.5 L container at 304 K contains 0.268 mol NH4HS(s), 0.133 M NH3 and 6.94×10-2 M H2S. What will be the concentrations of the two gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 8.86 L? [NH3] = [H2S] = ΣΣarrow_forwardThe equilibrium constant, Kp, for the following reaction is 1.04x102 at 548 K. NH4CI(S) NH3(9) + HCI(g) If an equilibrium mixture of the three compounds in a 5.40 L container at 548 K contains 2.83 mol of NH4Cl(s) and 0.186 mol of NH3(g), the partial pressure of HCI(g) is atm.arrow_forward
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