The equation of motion of a particle in simple harmonic motion is given by: x(t) = 0.2cos(wt), where x is in meters and t is in seconds. At x = 0, the particle's velocity is v = -1.256 m/s. The period of oscillation, T, equals: 1.5 sec 0.25 sec 1 sec 3 sec O 0.5 sec

A mass of 4.6 g is suspended from a massless spring of natural length 90 mm with the spring constant k = 3 Nm and causes the spring to extend by 10 mm. The mass is pulled down a further 5 mm and then released. Assuming g = 9.8 ms2, calculate the period of simple harmonic motion of the mass. Give your answer in Sl units.

The equation of motion for a mass of 4.0 kg on a horizontal spring (a simple harmonic oscillator) is x= (0.50 m)cos[(3.0 rad/s)t] (x is in meters and tis in seconds.) What is the period of this motion? O 2.1s 19 s 4.7 s 0.33 s

The equation of motion of a particle in simple harmonic motion is given by: x(t) = 0.2cos(wt), where x is in meters and t is in seconds. At x = 0, the particle's velocity is v = -1.256 m/s. The period of oscillation, T, equals: 0.25 sec 3 sec 1.5 sec 1sec 0.5 sec